A tent is in the shape of a triangular prism. The front and back are isosceles triangles with base 6 feet and height 4 feet. The surface area of the entire tent is 104 square feet. What is the depth of the tent?

Answers

Answer 1

Answer:

If surface area of the entire tent is 104 square feet then the depth of the tent is approximately 4.44 feet.

What is Three dimensional shape?

a three dimensional shape can be defined as a solid figure or an object or shape that has three dimensions—length, width, and height.

The tent can be divided into three rectangular faces and two triangular faces. Let the depth of the tent be denoted by "d".

The area of each triangularface is (1/2) base x height = (1/2) x 6 x 4 = 12 square feet.

The area of each rectangular face is length x width = d x 6 feet.

Therefore, the total surfacearea of the tent is:

2 x 12 square feet (for the triangular faces) + 3 x (d x 6 feet) square feet (for the rectangular faces) = 24 + 18d

We know that the total surface area of the tent is 104 square feet, so:

24 + 18d = 104

Subtract 24 from both sides.

18d = 80

Divide both sides by 18.

d = 80/18 ≈ 4.44 feet

Therefore, if surface area of the entire tent is 104 square feet then the depth of the tent is approximately 4.44 feet.

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Answer 2

Answer: the depth is 5 feet of the tent

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for a parabola at vertex (0,0)
we see that we have to go up and down
therfor it opens up or down

since focus is above directix, it opens up
x^2=4Py
p is distance from directix to vertex
since it opens up, P is positive
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x^2=4(5)y
x^2=20y
solve for y
divide both sides by 20
y=(1/20)x^2

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Answers

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