The dimensions are length equal to 9 inches and width equal to 6 inches.
It is given that length of rectangularframe is three less than twice the width and its perimeter is 30 inches.
We have to find out the dimensions of the frame.
What is the perimeter of a rectangle ?
The perimeter of a rectangle is 2 ( b + l ) , where b is width and l is the length of the rectangle.
As per the question ;
Length of rectangularframe is three less than twice the width.
Let's assume width be x.
So ;
Length will be ;
= 2x - 3
We know that ;
Perimeter of a rectangle is given by ;
P = 2 ( b + l )
⇒ 30 = 2 ( x + 2x - 3 )
⇒ 30 = 2 × ( 3x - 3 )
⇒ 30 = 6x - 6
⇒ 6x = 36
⇒ x = 6 inches
So ;
width will be 6 inches and length will be ;
l = 2x - 3
l = 2 × 6 - 3
l = 12 - 3
length = 9 inches
Thus , the dimensions are length equal to 9 inches and width equal to 6 inches.
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Answer:
V_rectangular_box = width x height x length
V = V_big_one + V_small_one
= (1/3)x(1/4)x(5/8) + (1/6)x(1/4)x(1/4) = 1/16 (ft3)
Answer:
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Step-by-step explanation:
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