The diameter of a circle is 21 inches. Find the area of the circle. (Use 22/7 as the approximation of pi.)

Answers

Answer 1
Answer:

Step-by-step explanation:

Area of a circle is pi times r-square

\pi \: {r}^(2)

So...

(22)/(7) * (21)/(2) * (21)/(2) = \frac{22 * {21}^(2) }{28}

Do the rest yourself, my calculator and pen are not handy.Sorry


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Write each sum as a product of the GCF of two numbers 75 and 90

Answers

75: 1, 3, 5, 15, 25, 75
90: 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90

GCF(75, 90) = 1, 3, 5, 15

1 × 3 × 5 × 15
3 × 75
225

You earn $420 per week. You pay social security taxes of 7.65%, federal taxes of 22%, and state taxes of 5.95%. What is your take home pay?

Answers

If you would like to know what is your take home pay, you can calculate this using the following steps:

social security taxes: $420 - 7.65% * $420 = 420 - 7.65/100 * 420 = $387.87
federal taxes: $387.87 - 22% * $387.87 = 387.87 - 22/100 * 387.87 = $302.54
state taxes: $302.54 - 5.95% * $302.54 = 302.54 - 5.95/100 * 302.54 = $284.54

Your take home pay would be $284.54.

Need help quiiickkkkIn 28.8 seconds, the piano plays 48 beats.
Piano Tempo
What is the tempo, in beats per minute, of the piano?
beats per minute

Answers

Answer:

100 beats per minute

Step-by-step explanation:

If it takes 28.8 secs for the piano to play 48 beats, then it would take 60 secs (1 minute) to play x number of beats.

To find the value of x, which is the number of beats the piano makes per minute, let's set the proportion as shown below:

28.8 secs = 48 beats

60 secs = x beats

Cross multiply

28.8*x = 60*48

28.8x = 2,880

Divide both sides by 28.8

x = 2,880/28.8

x = 100

✅Thus, if the Piano plays 48 beats in 28.8 secs, therefore, the tempo of the piano in beats per minute would be 100 BPM

Five years ago, Charlie was twice older than Priya. What are their ages now if in 3 years the sum of their ages will be 76?I need both ages thx

Answers

present age of charlie is  45 years

present age of priya is  25 years

Step-by-step explanation:

Let start from five years ago

Let at that age of Priya was x years

given that

Charlie was twice older than Priya

age of Charlie = 2x

_____________________________________________

present age of charlie = age 5 years ago + 5 years = 2x + 5

present age of priya = age of priya  5 years ago + 5 years x + 5 = x + 5

_________________________________________________

age of charlie 3 years from now = present age of charlie + 3 years

age of charlie 3 years from now =2x + 5 + 3 = 2x + 8

age of priya 3 years from now = present age of priya + 3 years

age of priya 3 years from now =x + 5 + 3 = x + 8

Given that

in 3 years the sum of their ages will be 76

thus

sum of their ages in 3 years from now = x + 8 + 2x + 8 = 76

=> 3x + 16 = 76

=> 3x = 76-16 = 60

=> x = 60/3 = 20

Thus,

present age of charlie =  2x + 5 = 2*20 + 5 = 45 years

present age of priya = x + 5 = 20 + 5 = 25 years

Complete the square and wright in standard form x^2+y^2-8x-12+52=36

Answers

x² + y² - 8x - 12y + 52 = 36
x² - 8x + y² - 12y + 52 = 36
x² - 8x + y² - 12y = 88
(x² - 8x + 16) + (y² - 12y + 36) = 88 + 16 + 36
(x - 4)² + (y - 6)² = 138
(h, k) = (x, y) = (4, 6)

x^2+y^2-8x-12y+52=36 \nx^2-8x+16+y^2-12y+36-16-36+52=36 \n(x-4)^2+(y-6)^2-52+52=36 \n\boxed{(x-4)^2+(y-6)^2=36}

CAN SOMEONE PLEASE HELP ME SOLVE THESE.ik it’s a lot but i really need some help
thank you

Answers

Answer:

a) 3p + 3q

b) 3a^2 + 4

c) -4ab + 24a

d) 3 (x - 2)

e) 3x + 7y

f) (x + 1) (2x + 3)

g) x^2 + x - 6

h) 6x^2 - 31x + 18

i) -5^2 + 6x +2y + 6

j) 2x^3 + 11x^2 + 17x + 6.

I answered question 1

Hope that helps. x

A 3x+3c
B 9x^2+12x
C -4ab+24a
D 3x-6
E 3x+3
F (x+1)(2x+3)
G x^2+x-6
H 6x^2-31x+18
I 6x-8y+11
J 2x^3+11x^2+17x+6

M=12

40

44

20

250/11

Last one is 33