What is the axis of symmsymmiof y=2(x+1)^2

Answers

Answer 1

Answer: y=a(x-h)^2+k
axis of symmetry is x=h

given
y=2(x-(-1)^2+0
h=-1
axis of symmetry is x=-1

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Computer usage has increased over time. But has the increase been more linear or more exponential? In 1997, 22.2% of the population over three years of age, or about 60 million people, used the internet. In 1998, 32.7% of the population over three years of age, or about 90 million people, used the internet. a. If the usage increased linearly, write the linear function that would give 60 million people in year 0 and 90 million in year 1.

Find 25% less than 56

Answers

Answer:the answer is 31

Step-by-step explanation:

We are looking for a new number which is 25 less than 56.

We will get the new number by subtracting 25 from 56.

We write it down as:

56-25=31

And finally the solution for: What number is 25 less than 56?

is 31

The rectangular vegetable garden in 6 feet longer than 2 times its width. If the perimeter is 48 feet, what is the garden's width? Remember, the perimeter of a rectangle is the sum of all its sides.

Answers

Since there are 4 sides in a rectangle, we'll divide 48 by 4

$(48)/(4)$ = 12

We know that the length is 6 feet longer than 2 times it width.

12 + 6 = 18

The length of one side of a rectangle is 18.

The total length of both sides is 36 because 18 + 18 = 36

48 - 36 = 12

The width of both sides of a rectangles is 12. Now if we divide 12 by 2 we'll get the width of one side of a rectangle..

$(12)/(2)$ = 6

The width of one side of the rectangle is 6.
The length of one side of the rectangle is 18.

Let's check and see if our answer is correct. We need to get a 48 as an answer since that's the perimeter of the rectangle.

2 × ( length + width )
2 × ( 18 + 6 ) = 48

Yay! We got it right!! Hope you understood this :)

Final answer:

The width of the garden is 6 feet. We found this by expressing the length in terms of width, substituting into the perimeter equation, simplifying to find the value of width.

Explanation:

In solving this problem, we will follow a few simple steps. First, we know that the perimeter of a rectangle is given by the formula: Perimeter = 2*length + 2*width. We know from the problem that the perimeter is 48 feet and the length of the garden is 6 feet longer than 2 times its width.

Let's denote the width as 'w'. Then, the length would be 2w + 6. Substituting these into the perimeter equation, we have: 48 = 2*(2w+6) + 2*w. Simplifying this equation gives 48 = 4w + 12 + 2w, which further simplifies to 48 = 6w + 12. If we now deduct 12 from both sides, we have: 36 = 6w. Finally, dividing by 6 gives us the width: w = 6 feet.

Learn more about Perimeter here:

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Whats the pattern in the numbers 4 16 36 64 100

Answers

...Every even # squared. 2^2=4, 4^2=16, 6^2=36, 8^2=64, 10^2=100.....

Pattern continued...4,16,36,64,100,144,196,256,324,400

Fourteen is 20% of what number?

Answers

fourteen is 20% of 70.

Answer:

Step-by-step explanation:

70 :)

What is the product of (x+1) and (2x^2+3x-1)?

Answers

(x + 1)(2x^2 + 3x - 1) : Can be solved in multiple ways but easiest for me :P

x (2x^2 + 3x - 1) + 1(2x^2 + 3x - 1)

(2x^3 + 3x^2 - x) + (2x^2 + 3x - 1)

2x^3 + 5x^2 + 2x - 1

Help geometry will give brainliest

Answers

The distance from the owl to the squirrel would be found by using the law of sins/co-sins

Cos (known angle) = adjacent leg / hypotenuse ( distance wanted)

cos(50) = 14 / x

x = 14 / cos50

x = 21.78 feet

The problem doesn't say if the answer should be rounded or not. You may have to round the answer if needed.

The angle of depression is congruent to your angle of elevation (the squirrel's line of sight. These are opposite angles. You use SOH CAH TOA to find the missing information because this forms a right triangle. SO you are really trying to solve for the hypotenuse here.
You are given the "side" opposite the angle. souse the SOH part Sine=opposite/hypotenuse
so when you plug in the information you get this equation:
sin(50)=14/x
divide both sides by sin(50) and you should get
a hypotenuse of approx. 18.3

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