It would be appreciated if all questions were answered and have shown work. :)1. While skiing, Sam flies down a hill and hits a jump. He has a mass of 75 kg, and he leaves the jump at 18 m/s. What is his momentum as he leaves the jump?


2. How fast would a 0.25 kg football have to be traveling to have the same momentum as a 0.05 kg bullet travelling 500 m/s?


3. Sarah, who has a mass of 55 kg, is riding in a car at 20 m/s. She sees a cat crossing the street and slams on the brakes! Her seat-belt stops her from flying forward, bringing her to rest in 0.5 seconds. How much force did the seat-belt put on Sarah?

Answers

Answer 1
Answer: 1. The formula for momentum is:
p = mv
p =75(18) = 1350 kg-m/s

2. We equate the momentum of the two objects
0.25 v = 0.05 (500)
v = 100 m/s

3. We use the formula for impulse:
Δmv = FΔt
55(20) = F(0.5)
F = 2200 N

Answer 2
Answer:

1)

P = mv  

P=75 (18) = 1350 kg-m/s


2)

0.25 v= 0.05 (500)

V= 100 m/s


3)

∆ mv = F∆t

55(20) =F(0.5)





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What is the purpose of the CETI program?a. to listen for disturbances in the earth's crust
b. to listen for unlawful broadcasts from rogue nations
c. to listen for signals from outer space
d. to listen for sounds emitted from the ocean

Answers

The purpose of the CETI program is c. to listen for signals from outer space. CETI stands for "Communication with ExtraTerrestrial Intelligence", and is a program dedicated to the search for extraterrestrial beings and intelligence. It mainly listens to sounds emitted from outer space, and analyzes/deciphers them in case they are part of another civilization.

Who established the 1st college course in radiography for dental students?

Answers

Howard Riley Raper, In 1909, Raper (a dentist at the Indiana Dental College, now known as Indiana University School of Dentistry) established the first course in dental radiography for dental undergraduate students.

Which of the following statements about geothermal energy is not true?a. It is not a practical source of energy.
b. It is an important source of energy in volcanically active areas.
c. It works best when the magma pool is near the surface of Earth.
d. It is a renewable source of energy.

Answers

Answer:

The answer is C

Explanation:

A 1000-kg car is moving along a straight road down a 30∘ slope at a constant speed of 20.0m/s. What is the net force acting on the car?

Answers

Answer:

net force acting on the car is zero

Explanation:

given data

mass of car = 1000 kg

slope = 30°

constant speed = 20.0 m/s

to find out

net force acting on the car

solution

we know here that car is moving with given 20 m/s velocity so here net force acting on the car will be zero

as net force is express as

Force = mass ×  acceleration    .....................1

and here acceleration is change of velocity per change in time

and here change in velocity is 0  

so that net force will be zero

so net force acting on the car is zero

Final answer:

In this scenario, the car is moving at a constant speed down a slope, which according to Newton's first law of motion, means that the net force acting on the car is zero.

Explanation:

The key to figuring out this problem lies within understanding Newton's first law of motion which states that an object will stay in constant motion as long as the net force acting upon it is zero. In this case, the car is moving at a constant speed implying that the net force, or the sum of all forces acting on it, equals zero. As the car moves down a slope, there's the force of gravity pulling it downwards and the normal force from the road acting upwards. When the car moves in a constant speed, these two forces are balanced, making the net force zero (0 Newtons).

Learn more about Net Force

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A cube of side 3.56 cm has a charge of 9.11 μ C placed at its center. Calculate the electric flux through one side of the cube

Answers

Answer:

\phi_(surface) = 1.72 * 10^5 N/Cm^2

Explanation:

As we know by the theory of flux that if charge "q" is enclosed in a closed surface then total flux through the surface is given as

\phi = (q)/(\epsilon_0)

so here total flux passing through the cube is given as

\phi_(total) = (9.11\muC)/(8.85 * 10^(-12))

now we will have

\phi_(total) = 1.03* 10^6

now as we know that charge is placed at the center of the cube

so the total flux is uniformly passing through all faces of the cube

so flux passing one side of the cube is given as

\phi_(surface) = (1.03* 10^6)/(6)

\phi_(surface) = 1.72 * 10^5 N/Cm^2

Flux=q/e0
e0=8.85*10^-12
!!! Cube has 6 sides, so flux through one side is equal to total flux/6
Ans=9.11*10^(-6)/((8.85*10(-12))*6)=(approximately)1.72*10^5Nm^2/C

Just after a motorcycle rides off the end of a ramp and launches into the air, its engine is turning counterclockwise at 8325 rev/min. The motorcycle rider forgets to throttle back, so the engine's angular speed increases to 12125 rev/min. As a result, the rest of the motorcycle (including the rider) begins to rotate clockwise about the engine at 4.2 rev/min. Calculate the ratio IE/IM of the moment of inertia of the engine to the moment of inertia of the rest of the motorcycle (and the rider). Ignore torques due to gravity and air resistance.

Answers

Answer:

(Ie)/(lm) = 1.10*10^(-3)

Explanation:

GIVEN DATA:

Engine operating speed nf = 8325 rev/min

engine angular speed ni= 12125 rev/min

motorcycle angular speed N_m= - 4.2 rev/min

ratio of moment of inertia of engine to motorcycle is given as

(Ie)/(lm) = (-N)/((nf-ni))

(Ie)/(lm) = (-(-4.2))/((12125 - (8325)))

(Ie)/(lm) = 1.10*10^(-3)

Answer:1.105* 10^(-3)

Explanation:

Given

Initial angular speed of engine(\omega _E)=8325 rpm

Final angular speed of engine(\omega _E_f)=12125 rpm

Initial angular speed of Motorcycle(\omega _M)=0 rpm

Final angular speed of engine(\omega _M_f)=4.2 rpm

as there is no external torque therefore angular momentum remains conserved

I_E\omega _E+I_M\omega _M=I_E\omega _E_f+I_M\omega _M_f

I_E\omega _E+=I_E\omega _E_f+I_M\omega _M_f

I_E\left ( \omega _E-\omega _E_f\right )=I_M\omega _M_f

(I_E)/(I_M)=(\omega _M_f)/(\omega _E-\omega _E_f)

(I_E)/(I_M)=(-4.2)/(8325-12125)=0.0011052\approx 1.105* 10^(-3)