What value of k solves the equation?

k-4=1/256

Answers

Answer 1
Answer: k-4=(1)/(256)\ \ \ \ \ \ \ \ \ \ |add\ 4\n\nk=(1)/(256)+4\n\nk=(1)/(256)+(1024)/(256)\n\nk=(1025)/(256)=4(1)/(256)
Answer 2
Answer: k-4=1/256
add 4 to both sides
k=4+1/256

k=4 and 1/256

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PLEASE HELP!!! a. segment AB congruent
segment CD
b. segment AB congruent d. segment BC
c. segment AD congruent segment BC
d. segment AC congruent segment BD

Answers

Answer:

A. Segment AB congruent segment CD

C. Segment AD congruent segment BC

Step-by-step explanation:

These are both true because a characteristic of a rhombus is that all four sides are congruent. Therefore we must prove that AB is congruent to CD and AD is congruent to BC.

Find the slope of the line passing through the points (2,-3) and (1,-5) .

Answers

Answer:

The slope of the line passing through the points (2, -3) and (1, -5) is 2.

The first four terms of a sequence are shown below: 7, 4, 1, -2 Which of the following functions best defines this sequence? A.f(1) = 7, f(n + 1) = f(n) + 3; for n ≥ 1 B.f(1) = 7, f(n + 1) = f(n) - 3; for n ≥ 1 C.  f(1) = 7, f(n + 1) = f(n) - 4; for n ≥ 1 D.f(1) = 7, f(n + 1) = f(n) + 4; for n ≥ 1

Answers

Answer:

Option (B) is correct.

The sequence that best defines the function is f(1) = 7, f(n + 1) = f(n) - 3; for n ≥ 1

Step-by-step explanation:

Given sequence 7 ,4, 1,-2

We have to choose a function from given options that best defines this sequence.

Let f(n) denotes the value at nth position,

Like f(1) = 7 , so here, n= 1.

Since next term is 4 = f(2)

4 can be written as 7 - 3 = f(1) -3

Next term is 1 = f(3)

1 can be written as 4-1 = f(2) - 3

Next term is -2 = f(4)

-2 can be written as 1-3 = f(3) - 3

Thus, following the sequence and writing in general form for n

f(n+1) = f (n) -3 , n ≥ 1

Thus, option (B) is correct.

The sequence that best defines the function is f(1) = 7, f(n + 1) = f(n) - 3; for n ≥ 1



answer is B.f(1) = 7, f(n + 1) = f(n) - 3; for n ≥ 1

f(1) = 7
f(2) = 7 -3 = 4
f(3) = 4 -3 = 1
f(4) = 1 -3 = -2

A grocery store clerk is putting cans of soup on the shelves.She has 12 boxes,wich each contain 24 cans of soup.Altogether,how many cans of soup will the clerk put ont he shelves

Answers

it's 12x24=288 problem solved

Joey's dog weighs 102.45 pounds. Jimmy's dog weighs 25.38 pounds less.How many pounds does Jimmy's dog weigh?

Answers


 1.Since 5 is less than 8, borrow 1 from the next column to make 15.



 2.Calculate 15 - 8, which is 7.


 3.Calculate 3 - 3, which is 0.

 4.Since 2 is less than 5, borrow 1 from the next column to make 12.


 5.Calculate 12 - 5, which is 7.


6..Calculate 9 - 2, which is 7.

7.Therefore, 102.45 - 25.38 = 77.07.
102.45 - 25.38 =77.07.

Tickets to a school dance cost $4 and the projected attendance is 300 people. For every $0.10 increase in ticket price, the dance committee projects that attendance will decrease by 5.Using formula R(4+.10t) (300-5t) where t is ticket price.

Determine the dance committee's greatest possible revenue. (Please show work as in #'s)

What ticket price will produce the greatest revenue? (Please show work as in #'s)

Answers

money made (R) = tickets sold * price of ticket
the number of $0.10 increases we make will be called t. so:
price of ticket =  $4 + $0.10t
tickets sold = 300 - 5t
R = (4 + .10t)(300 - 5t)
R = 1200 + 10t - .5t^2
R = -1/2t^2 + 10t + 1200
to find the maximum, we have to find the roots of this function.
0 = -1/2t^2 + 10t + 1200
0 = -t^2 + 20t + 2400
0 = t^2 - 20t - 2400
quadratic formula
t = 20 +- sqrt((-20)^2 - 4(1)(-2400)) all over 2(1)
t = 20+-sqrt(400+9600) all over 2
t = 20+-sqrt(10000) all over 2
t = 20+-100 all over 2
t = -80/2 or t=120/2
t = -40 or 60
now find the average of these roots. this will find the "middle" of the parabola, which is where the vertex (maximum) will be.
-40 + 60 all over 2
20/2
10
the vertex is at t=10. plug this into the formula:
R = -1/2t^2 + 10t + 1200
R = -1/2(10)^2 + 10(10) + 1200
R = 50 + 100 + 1200
R = 1350
therefore, the number of 10 cent price increases should be 10, because that will lead to total profits of $1350, the maximum possible. the ticket price will be $5.