Draw the graph of the line: with a slope of -1/2 and that passes through the origin

Answers

Answer 1
Answer:

To draw the graph of a line with a slope of -1/2 that passes through the origin (0, 0), we can use the slope-intercept form of a linear equation, which is y = mx + b, where 'm' is the slope and 'b' is the y-intercept.

In this case, the slope (m) is -1/2, and since the line passes through the origin, the y-intercept (b) is 0.

So, the equation of the line is y = (-1/2)x + 0, which simplifies to y = -1/2x.

Now, to plot the graph, start at the origin (0, 0). Since the y-intercept is 0, the line passes through the origin itself.

Next, use the slope (-1/2) to find other points on the line. The slope represents the change in y divided by the change in x. So, for every increase of 2 units in the x-direction (rise), the y-value decreases by 1 unit (run).

Plot additional points using this information and draw a straight line through all the points. The resulting graph is a downward-sloping line passing through the origin, representing the equation y = -1/2x.

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Answer 2
Answer:

Answer:

I hope this helps!


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How to solve which fraction is larger 10/13 or 11/14 or 14/15 or 17/18

Answers

To solve these type of problem you have to make the denominator the same or use the claculator.

let us do this problem by making the denominator the same.

(10)/(13) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (11)/(14) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (14)/(15)  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (17)/(18) \n\n (10)/(13)* (3780)/(3780) \ \ \ \ \ \ \ \ \ (11)/(14) * (3510)/(3510) \ \ \ \ \ \ \ \ \ (14)/(15) * (3276)/(3276) \ \ \ \ \ \ \ \ \ (17)/(18) * (2730)/(2730)

(37800)/(49140) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \    (38610)/(49140)  \ \ \ \ \ \ \ \ \ \ \ \ \ \    (45864)/(49140)  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \    (46410)/(49140)

So, now. the one with the largest numerator is the largest fraction

In this case, (46410)/(49140) is the largest which is equal to (17)/(18).

So, the largest fraction is (17)/(18).

Use the graphing calculator tool to plot the residualpoints. (1, 0.86), (2, -0.25), (3, -1.66), (4, -2.34), (5,-4.1)

Does the residual plot show that the line of best fit is
appropriate for the data?

A. Yes, the points have no pattern.

B. Yes, the points are evenly distributed about the x-axis.

C.No the points are in a linear pattern.

D.No, the points are in a curved pattern.

Answers

Answer: it’s option C: No, the points are in a linear pattern

Step-by-step explanation:

Took on edge

Final answer:

To determine if the line of best fit is appropriate for the data, plot the residuals on a graph and examine the pattern. In this case, the residual plot does not show a linear or curved pattern, indicating that the line of best fit is not appropriate for the data.

Explanation:

The residual plot shows the difference between the observed Y-values and the predicted Y-values. To plot the residuals, subtract the predicted Y-values from the observed Y-values for each corresponding X-value. Then plot the resulting points on a graph. In this case, the points are:

(1, 0.86), (2, -0.25), (3, -1.66), (4, -2.34), (5,-4.1).

To determine if the line of best fit is appropriate for the data, we need to examine the pattern of the residual plot. If the points have no pattern or are evenly distributed about the x-axis, it indicates that the line of best fit is appropriate. In this case, the points do not exhibit a linear or curved pattern, and they are not evenly distributed about the x-axis. Therefore, the residual plot does not show that the line of best fit is appropriate for the data.

Hence, the correct answer is: C. No the points are in a linear pattern.

The center of a circle is located at (3, 8), and the circle has a radius that is 5 units long. What is the general form of the equation for the circle? A. x2 + y2 − 6x − 16y + 48 = 0 B. x2 + y2 − 6x − 16y − 25 = 0 C. x2 + y2 + 6x + 16y + 48 = 0 D. x2 + y2 + 6x + 16y − 25 = 0

Answers

Answer:

  A.  x² +y² -6x -16y +48 = 0

Step-by-step explanation:

The standard-form equation for a circle centered at (h, k) with radius r is ...

   (x -h)² +(y -k)² = r²

For your circle, this is ...

  (x -3)² +(y -8)² = 5²

To put this in general form, you subtract the constant on the right, and eliminate parentheses:

  x² -6x +9 +y² -16x +64 -25 = 0

  x² +y² -6x -16y +48 = 0 . . . . . rearrange to descending powers of x, y

An equivalent fraction for 2/3 is
1. 2/6
2. 1/3
3. 8/15
4. 10/15

Answers

As the given and answers are all fractions, this is merely a trial-and-error method to simplify and see which answers are equivalent to the given fraction. So let us try with all them:

1.) 2/6 = 1/3 (X)
2.) 1/3 is already simplified and is not equivalent to 2/3. (X)
3.) 8/15 is already simplified and is not equivalent to 2/3. (X)
4.) 10/15 = 2/3 (by dividing 5 from both numerator and denominator)

Therefore, the correct answer is 10/15


Are there any maths genius here can help?​

Answers

Answer:

1 》let equal side be X and other side y

now, length of y= 2x sin teta/2

=12.3×sin42/2

=12.3 × sin21

=4.407

Find the first five terms of the sequence defined by each of these recurrencerelations and initial conditions.
a) an = 6an-1, a0 = 2
b) an = −2an-1, a0 = −1
c) an = an-1 – an-2, a0 = 2, a1 = −1

Answers

a) The first five terms of the sequence are 2, 12, 72, 432, 2592.
b) The first five terms of the sequence are -1, 2, -4, 8, -16.

c) The first five terms of the sequence are 2, -1, -3, -2, 1.

To find the first five terms of the sequence defined by each of these recurrence relations and initial conditions, we will use the given recurrence relation and initial conditions to find the next terms in the sequence.

a) an = 6an-1, a0 = 2

The first term is given as a0 = 2. We will use the recurrence relation to find the next terms.
a1 = 6a0 = 6(2) = 12
a2 = 6a1 = 6(12) = 72
a3 = 6a2 = 6(72) = 432
a4 = 6a3 = 6(432) = 2592

So, the first five terms of the sequence are 2, 12, 72, 432, 2592.

b) an = −2an-1, a0 = −1

The first term is given as a0 = -1. We will use the recurrence relation to find the next terms.
a1 = -2a0 = -2(-1) = 2
a2 = -2a1 = -2(2) = -4
a3 = -2a2 = -2(-4) = 8
a4 = -2a3 = -2(8) = -16

So, the first five terms of the sequence are -1, 2, -4, 8, -16.

c) an = an-1 – an-2, a0 = 2, a1 = −1

The first two terms are given as a0 = 2 and a1 = -1. We will use the recurrence relation to find the next terms.
a2 = a1 - a0 = -1 - 2 = -3
a3 = a2 - a1 = -3 - (-1) = -2
a4 = a3 - a2 = -2 - (-3) = 1

So, the first five terms of the sequence are 2, -1, -3, -2, 1.

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