To draw the graph of a line with a slope of -1/2 that passes through the origin (0, 0), we can use the slope-intercept form of a linear equation, which is y = mx + b, where 'm' is the slope and 'b' is the y-intercept.
In this case, the slope (m) is -1/2, and since the line passes through the origin, the y-intercept (b) is 0.
So, the equation of the line is y = (-1/2)x + 0, which simplifies to y = -1/2x.
Now, to plot the graph, start at the origin (0, 0). Since the y-intercept is 0, the line passes through the origin itself.
Next, use the slope (-1/2) to find other points on the line. The slope represents the change in y divided by the change in x. So, for every increase of 2 units in the x-direction (rise), the y-value decreases by 1 unit (run).
Plot additional points using this information and draw a straight line through all the points. The resulting graph is a downward-sloping line passing through the origin, representing the equation y = -1/2x.
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Answer:
I hope this helps!
Does the residual plot show that the line of best fit is
appropriate for the data?
A. Yes, the points have no pattern.
B. Yes, the points are evenly distributed about the x-axis.
C.No the points are in a linear pattern.
D.No, the points are in a curved pattern.
Answer: it’s option C: No, the points are in a linear pattern
Step-by-step explanation:
Took on edge
To determine if the line of best fit is appropriate for the data, plot the residuals on a graph and examine the pattern. In this case, the residual plot does not show a linear or curved pattern, indicating that the line of best fit is not appropriate for the data.
The residual plot shows the difference between the observed Y-values and the predicted Y-values. To plot the residuals, subtract the predicted Y-values from the observed Y-values for each corresponding X-value. Then plot the resulting points on a graph. In this case, the points are:
(1, 0.86), (2, -0.25), (3, -1.66), (4, -2.34), (5,-4.1).
To determine if the line of best fit is appropriate for the data, we need to examine the pattern of the residual plot. If the points have no pattern or are evenly distributed about the x-axis, it indicates that the line of best fit is appropriate. In this case, the points do not exhibit a linear or curved pattern, and they are not evenly distributed about the x-axis. Therefore, the residual plot does not show that the line of best fit is appropriate for the data.
Hence, the correct answer is: C. No the points are in a linear pattern.
Answer:
A. x² +y² -6x -16y +48 = 0
Step-by-step explanation:
The standard-form equation for a circle centered at (h, k) with radius r is ...
(x -h)² +(y -k)² = r²
For your circle, this is ...
(x -3)² +(y -8)² = 5²
To put this in general form, you subtract the constant on the right, and eliminate parentheses:
x² -6x +9 +y² -16x +64 -25 = 0
x² +y² -6x -16y +48 = 0 . . . . . rearrange to descending powers of x, y
1. 2/6
2. 1/3
3. 8/15
4. 10/15
Answer:
1 》let equal side be X and other side y
now, length of y= 2x sin teta/2
=12.3×sin42/2
=12.3 × sin21
=4.407
a) an = 6an-1, a0 = 2
b) an = −2an-1, a0 = −1
c) an = an-1 – an-2, a0 = 2, a1 = −1
a) The first five terms of the sequence are 2, 12, 72, 432, 2592.
b) The first five terms of the sequence are -1, 2, -4, 8, -16.
c) The first five terms of the sequence are 2, -1, -3, -2, 1.
To find the first five terms of the sequence defined by each of these recurrence relations and initial conditions, we will use the given recurrence relation and initial conditions to find the next terms in the sequence.
a) an = 6an-1, a0 = 2
The first term is given as a0 = 2. We will use the recurrence relation to find the next terms.
a1 = 6a0 = 6(2) = 12
a2 = 6a1 = 6(12) = 72
a3 = 6a2 = 6(72) = 432
a4 = 6a3 = 6(432) = 2592
So, the first five terms of the sequence are 2, 12, 72, 432, 2592.
b) an = −2an-1, a0 = −1
The first term is given as a0 = -1. We will use the recurrence relation to find the next terms.
a1 = -2a0 = -2(-1) = 2
a2 = -2a1 = -2(2) = -4
a3 = -2a2 = -2(-4) = 8
a4 = -2a3 = -2(8) = -16
So, the first five terms of the sequence are -1, 2, -4, 8, -16.
c) an = an-1 – an-2, a0 = 2, a1 = −1
The first two terms are given as a0 = 2 and a1 = -1. We will use the recurrence relation to find the next terms.
a2 = a1 - a0 = -1 - 2 = -3
a3 = a2 - a1 = -3 - (-1) = -2
a4 = a3 - a2 = -2 - (-3) = 1
So, the first five terms of the sequence are 2, -1, -3, -2, 1.
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