Homologous structures in two species indicate that they share a common ancestor. These structures, although they may serve different functions in adult organisms, have a similar form and the same embryonic origin. They provide key evidence for evolution and development of various species from common ancestors.
The presence of homologous structures in two different species often demonstrates an evolutionary relationship, indicating they share common ancestry. Homologous structures are those that have a similar form or function and share a similar embryonic origin, although they may appear different and perform different functions in the adult organisms. An example of this could be the bone structure in a human arm, cat leg, whale flipper, and bat wing which, despite serving different purposes, all have a similar arrangement of bones.
The presence of such structures suggests that these species have evolved from a common ancestor that had this structure. Over time, as the species evolved and adapted to their specific environments or lifestyles, these structures may have developed different functions. Therefore, homologous structures are key evidence for the theory of evolution and help in developing phylogenetic relationships. They help us understand how different species have evolved and diversified from common ancestral forms.
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Answer:
C: A solid metal ball in the middle of a pool of liquid.
Explanation:
Since the student is studying the earth, the core area is made up of a solid metal ball in the middle of a pool of a liquid.
• all forests populations
• plants fungi and microbes in the forest
• rushing stream
• rock on which turtles and
frogs sit
please i am really confused and my test is timed so please can someone answer fast :(
Answer:
every squirrel in the forest
all forests populations
plants, fungi and microbes in the forest
Explanation:
In ecology, a community refers to a population of different species of organisms occupying a particular area at a particular time. In other words, community is a group of living organisms of different species interacting with one another in a given habitat.
According to the question, a forest community will contain all plants, animals and microbes in the forest involved in a series of interaction with one another. This includes every squirrel in the forest, all population of organisms in the forest and all plants, fungi and microbes in the forest.
N.B: If the abiotic components are included to the living ones, they will together make up an ECOSYSTEM.
Answer:
Explanation:
everything must match up inorder to find anyone accountiable
For forensic science, the Gas Chromatography-Mass Spectrometry (GC-MS) is highly reliable and accurate for identifying specific materials. In a case involving a paint chip, it accurately identifies the various elements and compounds in the paint and discriminates between different paint brands and types.
In the entire arsenal of forensic tests, one test stands out for its high reliability and accuracy in identifying specific materials: the Gas Chromatography-Mass Spectrometry (GC-MS). It has two main components: Gas Chromatograph, which separates the different components in a substance, and Mass Spectrometer, which identifies each of these components.
The GC-MS test is particularly effective when analyzing biological materials like blood, saliva, and even paint fragments. When dealing with a case involving a paint chip, for instance, GC-MS can not only identify the various elements and compounds in the paint but can discriminate between different paint brands and types, thereby increasing the probability of accurately matching the paint chip to a specific car.
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Final answer:
When crossing a heterozygous round, tall F1 pea plant with a homozygous wrinkled, short pea plant, the probability of the offspring being wrinkled and tall is 1/4.
Explanation:
In pea plants, we have two traits where round seed shape (R) is dominant to wrinkled seed shape (r), and tall height (T) is dominant to short height (t). When a homozygous round, tall plant (RRTT) is crossed with a homozygous wrinkled, short plant (rrtt), the resulting F1 generation will all have the genotype RrTt (heterozygous for both traits). If these F1 plants are then crossed back to the wrinkled, short strain (rrtt), we need to look at each trait separately to determine the phenotype ratios.
For the seed shape, the F1 plants (Rr) crossed with the wrinkled, short (rr) can produce offspring with either Rr or rr genotype. Therefore, the probability of having a wrinkled (rr) offspring is 1/2. For height, the F1 plants (Tt) crossed with the wrinkled, short (tt) can also produce offspring with either Tt or tt genotype. The probability of having a tall (Tt) offspring is 1/2 as well. To find the proportion of offspring that are wrinkled and tall, we multiply the probabilities of the independent events: 1/2 (chance of being wrinkled) × 1/2 (chance of being tall) which equals 1/4.
Therefore, the proportion of offspring that will be wrinkled and tall from this cross is 1/4.
There are many, and since you didn't specify the choices, some examples include "ff" or "dd" or just two lowercase letters.
Explanation: