What is the LCM of 13 and 26

Answers

Answer 1
Answer: The lest common multiple is 26. If you do multiples of each number

13:13,26
26: 26

Both of their lest common multiples would be 26
Answer 2
Answer: LCM\ is\ the\ least\ common\ number\ that\ is\ multiply\ of\ both:\n\n Factors\ of\ 13\n 13:13\n\n Factors\ of\ 26:\n 26:2\n 13:13\n\n LCM(13,26)=2*13=26\n\n \textbf{LCM(13,26)=26}

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I'm trying to figure this problem out

How to factor x^3-4x^2+5x-20 with (x-2)?

Answers

Answer:

Step-by-step explanation:

hello :

x^3-4x^2+5x-20 = x²(x-4)+5(x-4) = (x-4)(x²+5)

The coordinates of the vertices of a polygon are (-2, 1). (-3, 3), (-1, 5), (2, 4), and (2, 1). What is the perimeter of the polygon to the nearest tenth of a unit. Do not label your answer. Answer with a number only.

Answers

Answer:

15.2\ units

Step-by-step explanation:

step 1

Plot the vertices of the polygon to better understand the problem

we have

A(-2, 1). B(-3, 3), C(-1, 5), D(2, 4),E(2, 1)

using a graphing tool

The polygon is a pentagon (the number of sides is 5)

see the attached figure

The perimeter is equal to

P=AB+BC+CD+DE+AE

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^(2)+(x2-x1)^(2)}

step 2

Find the distance AB

A(-2, 1). B(-3, 3)

substitute in the formula

d=\sqrt{(3-1)^(2)+(-3+2)^(2)}

d=\sqrt{(2)^(2)+(-1)^(2)}

d_A_B=√(5)=2.24\ units

step 3

Find the distance BC

B(-3, 3), C(-1, 5)

substitute in the formula

d=\sqrt{(5-3)^(2)+(-1+3)^(2)}

d=\sqrt{(2)^(2)+(2)^(2)}

d_B_C=√(8)=2.83\ units

step 4

Find the distance CD

C(-1, 5), D(2, 4)

substitute in the formula

d=\sqrt{(4-5)^(2)+(2+1)^(2)}

d=\sqrt{(-1)^(2)+(3)^(2)}

d_C_D=√(10)=3.16\ units

step 5

Find the distance DE

D(2, 4),E(2, 1)

substitute in the formula

d=\sqrt{(1-4)^(2)+(2-2)^(2)}

d=\sqrt{(-3)^(2)+(0)^(2)}

d_D_E=√(9)\ units

d_D_E=3\ units

step 6

Find the distance AE

A(-2, 1).E(2, 1)

substitute in the formula

d=\sqrt{(1-1)^(2)+(2+2)^(2)}

d=\sqrt{(0)^(2)+(4)^(2)}

d_A_E=√(16)\ units

d_A_E=4\ units

step 7

Find the perimeter

P=AB+BC+CD+DE+AE

substitute the values

P=2.24+2.83+3.16+3+4=15.23\ units

Round to the nearest tenth of a unit

P=15.2\ units

Can two squares of different sizes have the same perimeter

Answers

No. All four sides of a square have the same length, so each square's perimeter is 4s. If you make insert any number in there, the output will always be different.

s  I  y
--------
1  I 4
2  I 8 
3  I 12
4  I 16
...

*HELP PLEASE WILL THANK AND AWARD BRAINLIEST ANSWER*Given figure ABCD ~ figure KLMN, what is the value of y?   

A.
1.2 cm
  
B.
3.6 cm
 
C.
4 cm
 
D.
12 cm

Answers

big trapezoid: upper base = 4 cm ; lower base = 12cm ; side = 10cm
small trapezoid: upper base = y ; lower base = ? ; side = 3cm

Figure ABCD is contracted into figure KLMN, this means that they have the same proportion as to the other sides of the figure.

side: 10 cm / 3cm = 3.33
upper base: 4cm / 3.33 = 1.20  value of y.
lower base: 12cm / 3.33 = 3.60

4/10 = 0.40 ; 1.20/3 = 0.40
4/12 = 0.33 ; 1.20/3.6 = 0.33
10/12 = 0.83; 3/3.60 = 0.833

Tony's math grades are 85, 92, 95, 81, and 92. What is his average grade in math?

Answers

Answer:

89

Step-by-step explanation:

85+92+95+81+92=445 and since there are 5 numbers you're going to divide by 5 so 445/5 which is 89

Answer:

The answer to your problem would be 89

Step-by-step explanation:

A backyard fence 80 feet long; 1 inch = 10feet

Answers

Hi there, 1 inch = 10 feet, and you asked for 80 feet, 10*8=80. We do 80/10 and that would give us 8,