Answer:
1. How many ATOMS of boron are present in 2.20 moles of boron trifluoride? atoms of boron.
2. How many MOLES of fluorine are present in of boron trifluoride? moles of fluorine.
Explanation:
The molecular formula of boron trifluoride is .
So, one mole of boron trifluoride has one mole of boron atoms.
1. The number of boron atoms in 2.20 moles of boron trifluoride is 2.20 moles.
The number of atoms in 2.20 moles of boron is:
One mole of boron has ---- atoms.
Then, 2.20 moles of boron has
-
2. Calculate the number of moles of BF3 in 5.35*1022 molecules.
One mole of boron trifluoride has three moles of fluorine atoms.
Hence, 0.0888moles of BF3 has 3x0.0888mol of fluorine atoms.
=0.266mol of fluorine atoms.
Answer:
OBSERVING AND QUESTIONING
Explanation:
when you use the scienfic method the first thing you have to do is question you theory and coming up with a hypothesis which is what you expect to happen
Answer:
make an observation
Explanation:
b. linear growth
c. fertility
d. biotic growth
User: As a population reaches its carrying capacity, there is an increase in competition for
a. food.
b. shelter.
c. mates.
d. All of the above
Answer:
1. A
2. D
Explanation:
1. If a population is left unrestricted, meaning it is not limited to anything, then the population will continue to increase exponentially due to there being no limits.
2. If a population is limited, and it has reached its carrying capacity, then the essential needs of life are being competed for. Things like food, shelter, and mates are now a limited resource, and hence the option would be "all of the above".
FeCl3
Fe2(SO4)3
PbO
PbO2
Pb3O4
Answer:
The final solution will be clear and colorless.
Explanation:
The balanced reaction equation is:
NaOH + HCl ⇒ H₂O + NaCl
The amount of NaOH that is added is calculated as follows:
(20.0mL)(1.0mol/L) = 20 mmol NaOH
Similarly, the amount of HCl that is added is as follows:
(10.0mL)(1.0mol/L) = 10 mmol HCl
Since HCl and NaOH react in 1:1 proportions, the HCl is the limiting reaction. 10 mmmol of HCl will neutralize 10 mmol of NaOH, leaving 10 mmol of NaOH. The volume of the mixed solution is 30.0 mL, so the concentration of NaOH in the final solution is:
(10 mmol)/(30.0mL) = 0.3333 M NaOH
The pOH of the final solution is:
pOH = -log([OH⁻) = -log(0.3333) = 0.477
The pOH is related to the pH as follows:
pH = 14 - pOH = 14 - 0.477 = 13.5
At a pH of 13.5, phenolphthalein is colorless. The final solution will be observed as clear and colorless.