Answer:
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Answer:
irrational
Step-by-step explanation:
b.) Trina is correct because the two sides of the equation are not equivalent
c.) Trina is not correct because the two sides of the equation are equivalent
d.) Trina is not correct because the two sides of the equation are not equivalent
I'm super confused on this can somebody help me
The answer is C Trina is not correct because the two sides of the equation are equivalent
B. y = -3(x + 3)2 - 6
C. y = -3(x - 3)2 + 6
D. y = -3(x - 3)2 - 6
Based on the calculations, the equation of this parabola is equal to: A. y = -3(x + 3)² + 6.
Mathematically, the standard equation with the vertex for any parabola is given by:
y = a(x - h)² + k.
where:
Substituting the given parameters into the formula, we have;
y = -3(-3 - (-3))² + 6
y = -3(x + 3)² + 6
Read more on parabola here: brainly.com/question/2346582
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B. It will be smaller than the original triangle
C. It will be congruent to the original triangle
D. It will be a different shape then the original triangle
The triangle formed from reflecting the original triangle across the y-axis and then translating it 5 units to the right will be congruent to the original triangle.
The triangle formed from reflecting the original triangle across the y-axis and then translating it 5 units to the right will be congruent to the original triangle.
When a figure is reflected across the y-axis, its shape remains the same, but its orientation is flipped. Then, by translating the reflected triangle 5 units to the right, we are simply shifting it horizontally without changing its size or shape.
Therefore, the statement that is true about the triangle formed from these transformations is C. It will be congruent to the original triangle.
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Answer: (A) vertical asymptote: x = 2, horizontal asymptote: y = 1
Step-by-step explanation:
Vertical Asymptote is the restriction on the x-value. The denominator cannot be zero, so x - 2 ≠ 0 ⇒ x ≠ 2
The restricted value on x is when x = 2 which is the vertical asymptote
Horizontal Asymptote (H.A.) is the restriction on the y-value. This is a comparison of the numerator (n) and denominator (m). There are 3 rules that will help you:
In the given problem, n < m so y = 0, however there is also a vertical shift of up 1 so the H.A. also shifts up. This results in H.A. of y = 1