The equation for the circle below is x2 + y2 = 100. What is the length of the
circle's radius?

Answers

Answer 1
Answer:

Answer:

Step-by-step explanation:

x²+y² =(Radius)²

x²+y² =10². So the radius is 10

Answer 2
Answer:

Answer:

radius = 10

Step-by-step explanation:

The equation of a circle centred at the origin is

x² + y² = r² ( where r is the radius )

x² + y² = 100 ← is in this form

with r² = 100 ( take the square root of both sides )

r = √(100) = 10


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Find the cost for renting a car for six days at $24.75 per day and 13¢ per mile, if the car is driven 1,083 miles.A. $148.50
B. $289.29
C. $140.79
D. $278.29

Answers

Answer:

Step-by-step explanation:

13per mile×1080 mile =140.79

Answer:

B

Step-by-step explanation:

if you at $24.74 * 6 = 148.5

then you take 1083 * .13 = 140.79

then add the two number to get 289.29

What is the slope between two points 12,6 and 20,22

Answers

The slope of a line between 2 points is given by the formula

m = y2 - y1/x2 - x1

m= 22-6/20-12

m= 16/8= 2

slope is 2
slope is 2 hoe it helped

The breakfast special served at Pancake Heaven includes 2 eggs and 1 waffle. Last week, 333 people were served the breakfast special. Based on that amount, how many eggs are needed for the number of breakfast specials that will be served during a 1-year period (52 weeks)?

Answers

34,632 eggs, because 333 people with two eggs per person is 666 eggs, and 666 times 52 is 34,632

What is the solution to the system of equations below?y=-x-4 and y=-2x-9
O (-2,-5)
O (-2, -3)
O (2, -3)
O (2, -13)


I need to know for my test plzz it’s timed

Answers

Answer:b

Step-by-step explanation:

19. (3,5), (2,-2)write an equation in slope-intercept form for the line that passes through each pair of points

Answers

Answer:

y=7x−16       the answer ;)

Simplify $(1-3i)(1-i)(1+i)(1+3i)$

Answers

(1-3i)(1-i)(1+i)(1+3i)=\n(1^2-(3i)^2)(1^2-i^2)=\n(1+9)(1+1)=\n10\cdot2=20

Answer:

\huge\boxed{(1-3i)(1-i)(1+i)(1+3i)=20}

Step-by-step explanation:

(1-3i)(1-i)(1+i)(1+3i)\n\n\text{use the commutative property}\n\n=(1-3i)(1+3i)(1-i)(1+i)\n\n\text{use the associative property}\n\n=\bigg[(1-3i)(1+3i)\bigg]\bigg[(1-i)(1+i)\bigg]\n\n\text{use}\ (a-b)(a+b)=a^2-b^2\n\n=\bigg[1^2-(3i)^2\bigg]\bigg[1^2-i^2\bigg]\n\n=\bigg(1-9i^2\bigg)\bigg(1-i^2\bigg)\n\n\text{use}\ i=√(-1)\to i^2=-1\n\n=\bigg(1-9(-1)\bigg)\bigg(1-(-1)\bigg)\n\n=\bigg(1+9\bigg)\bigg(1+1\bigg)\n\n=(10)(2)\n\n=20