I need help choosing which multiple choice the answer would be ?

Answers

Answer 1

Answer: Add 6 to both sides
So answer B

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Which two solid figures have the same volume?A. A rectangular solid with a base of 6 cm2 and a height of 12 cm B. An oblique solid with a base of 6 cm2 and a slant height of 12cm C. A cone with a base of 6 cm2 and a height of 12 cm D. An oblique solid with a base of 6 cm2 and a height of 12 cm
Which polygons are congruent?

Are the triangles similar?

Answers

No the side’s are different

On the distant planet Cowabunga, the weights of cows have a normal distribution with a mean of 483 pounds and a standard deviation of 70 pounds. The cow transport truck holds 5 cows and can hold a maximum weight of 2840. If 5 cows are randomly selected from the very large herd to go on the truck, what is the probability their total weight will be over the maximum allowed of 2840

Answers

Answer: 0.0033

Step-by-step explanation:

Let x be a random variable that denotes the weights of cows.

Given: $\mu = 483,\ \sigma=70$

maximum weight can be hold= 2840 pounds.

Mean weight = $(2840)/(5)$ = 568 pounds

The probability their total weight will be over the maximum allowed of 2840

= $P(X>2840)$

$P((x-\mu)/((\sigma)/(√(n)))>(568-483)/((70)/(√(5))))\n\n=P(z>2.715)\n\n=1-P(z<2.715)\n\n=1-0.9967=0.0033$

Hence, the required probability = 0.0033

Mr.mays drove 20 miles in 24 minutes. At this rate ,how many miles did he drive in 6 minuts

Answers

20 miles .... 24 minutes
x miles ... 6 minutes

We would like to know how many miles did he drive in 6 minutes (x miles). You can calculate this in the following way:

20 * 6 = 24 * x
120 = 24 * x /24
x = 120 / 24
x = 5 (miles)

The result is 5 miles.

A distributor needs to mix some Terraza coffee that normally sells for $9.00 per pound with some Kona coffee that normally sells for $13.50 per pound to create 50 pounds of a mix that can sell for $9.54 per pound. How many pounds of each kind of coffee should they mix?

Answers

Answer:

Step-by-step explanation:

Mixture problems are really easy because the table never varies from one problem to another and they don't have a lot of variations in them like motion problems do. The table for us will look like this, using T for Terraza coffee and K for Kona:

#lbs x $/lb = Total

Mix

Now we just have to fill this table in using the info given. We are told that T coffee is $9 per pound, and that K coffee is $13.50 per pound, so we will fill that in first:

#lbs x $/lb = Total

T 9

K 13.50

Mix

Next we are told that the mix is to be 50 pounds that will sell for $9.54 per pound

#lbs x $/lb = Total

T 9

K 13.50

Mix 50 9.54

Now the last thing we have to have to fill in this table is what goes in the first column in rows 1 and 2. If we need a mix of 50 pounds of both coffees and we don't know how many pounds of each to use, then under T we have x and under K we have 50 - x. Notice along the top we have that the method to use to solve this problem is to multiply the #lbs by the cost per pound, and that is equal to the Total. So we'll do that too:

#lbs x $/lb = Total

T x x 9 = 9x

K 50 - x x 13.50 = 675 - 13.50x

Mix 50 x 9.54 = 477

The last column is the one we focus on. We add the total of T to the total of K and set it equal to the total Mix:

9x + 675 - 13.5x = 477 and

-4.5x = -198 so

x = 44 pounds. This means that the distributor needs to mix 44 pounds of T coffee with 6 pounds of K coffee to get the mix he wants and to sell that mix for $9.54 per pound.

−15x+4x+2−x=____x+ 3