Suggest one reason why the experiment might not have given a correct value forthe specific heat capacity of the metal.

A) The temperature at the fat-inner fur boundary be so that the bear loses heat at a rate of 51.4W is; T_i = 38.52°C

B) The thickness of the layer contained within the fur so that the bear loses heat at a rate of 51.4 W is; t = 13.41 cm

We are given;

Diameter of sphere; d = 1.6 m

Radius of sphere; r = d/2

r = 1.6/2

r = 0.8 m

Thickness of bear; t = 3.9 cm cm = 0.039 m

Outer surface Temperature of fur; T_h = 2.8 ∘C

Inner surface Temperature of fat;T_f = 30.9 ∘C

Thermal conductivity of fat; K_f = 0.2 W/m⋅k

Thermal conductivity of air; K_a = 0.024 W/m⋅k

A) To find the temperature at the fat-inner fur boundary when heat loss is 51.4 W, we will use the heat current formula;

H = K_f•A(T_f - T_i)/t

Where;

A is area = 4πr²

A = 4π × 0.8²

A = 8.04 m²

T_i is the temperature we are looking for

H is heat loss = 51.4

t is thickness

Making T_i the subject gives;

T_i = (T_f × H × t)/(K_f × A)

T_i = (30.9 × 51.4 × 0.039)/(0.2 × 8.04)

T_i = 38.52°C

B) We want to find the thickness of the layer contained within the fur. Thus, we will use K_a instead of K_f. Let us make t the subject in the heat current formula to get;

t = (K_a•A(T_i - T_h)/H

t = (0.024 × 8.04 × (38.52 - 2.8))/51.4

t = 0.1341 m

t = 13.41 cm

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Answer:

Explanation:

Using the equation

H = Q/t = k A ( T hot - T cold) / L

where H is the rate of heat loss = 51.4 W, T cold be temperature of the outer surface, A is the surface area of the fat layer which is a model of sphere ( surface area of a sphere ) = 4πr² where diameter = 1.60 m

radius = 1.60 m / 2 = 0.80 m

A = 4 × 3.142 × ( 0.8²) = 8.04352 m²

making T cold subject of the formula

T cold =  T hot -    = 30.9° C - ( 51.4 W × 3.9 × 10⁻² m) / ( 0.2 W/mK × 8.04352 m² ) =  30.9° C - 1.25 ° C = 29.65° C

b) The thickness of air layer for the bear to lose heat t a rate of 51.4 W

thermal conductivity of air is 0.024 W/mK and rearranging the earlier formula

L = = (0.024 W/ m K × 8.04352 m²) ( 29.65° C - 2.8°C) / 51.4 W = 0.101 m = 10.1 m

Okay so we need to bring a couple of equations into this

First E =F/q

We have our q and E lets solve for F

F = Eq

So remember th equation

F = qV x B

F = qVBsin(Ф)

The angle is perpendicular so

sin(90) = 1

F = qVB

Solve for V

F/qB = V

Eq/qB = V

Look at that the charges cancel out!

V = E/B

(Fun fact: Thats what they use in mass spectrometers which is why it says the particle should travel in a straight line)

Anyways lets solve this!

V = 2/5

V = 0.4 m/s

there are 2 forces acting on the particle: magnetic n electric force

the 2 forces must be equal 4 it to travel in a straight line

as it has +1C charge, q, the charge is dropped in the following:

magnetic force = qv x B where v is velocity n B is magnetic field;

x represents cross-product which in this case of 90-deg. is same as multiply

magnet force = v*5

electric force = qE where E is electric field

= 2

as magnet force = electric force

v*5 = 2

v=2/5=0.400m/s

Answer:

magnitude of force is 1725 N

direction is opposite to the direction of car moving  i.e west

Explanation:

Given data

car mass = 1380 kg

speed = 27.0 m/s

time = 8 s

speed = 17 m/s

to find out

magnitude and direction of the net force

solution

we find here first acceleration thats formula is

a = v(initial) - v(final) / time

a =27 - 17 / 8

acceleration = 1.25 m/s

so force is = ma

force is = 1380 ( 1.25)

force = 1725 N

so magnitude of force is 1725 N

and this is here direction is opposite to the direction of car moving  i.e west

Final answer:

The net force that leads to the deceleration of the 1380 kg car from 27.0 m/s to 17.0 m/s over 8.00 seconds has a magnitude of 1725 N and is directed towards the west.

Explanation:

To solve for the magnitude and direction of the net force that produces the deceleration in the car, you first need to calculate the acceleration and then use it to find the net force using the formula f = m * a. The acceleration here represents a deceleration because the speed is decreasing.

Acceleration can be found using the formula a = (v_f - v_i) / t. Here, v_i is the initial speed (27.0 m/s), v_f is the final speed (17.0 m/s), and t is the time interval (8.00 s). This gives you a = (17.0 m/s - 27.0 m/s) / 8.00 s = -1.25 m/s^2. The negative sign represents deceleration.

Now, apply this deceleration to the formula for force, f = m * a. Here, m is the mass of the car (1380 kg) and a is the value we computed (-1.25 m/s^2). So, f = 1380 kg * -1.25 m/s^2 = -1725 N. The negative sign indicates that the force is in the direction opposite to the initial motion of the car. Therefore, the magnitude of the net force is 1725 N, and the direction is towards the west or opposite to the car's original path.

Learn more about Net Force Calculation here:

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Answer:

3.0

Same explanation as the person above but the significant figures must be considered in physics.