Here, we are required to evaluate tan(sin^-1 (-4/5)).
tan(sin^-1 (-4/5)) = (-4/3)
Sin^-1 (-4/5) = θ
Therefore; ultimately Sin θ = (-4/5)
Since; Sine = opposite / hypothenus
Therefore, adj = √(5²) - (4²)
adj = 3.
However, since tan(sin^-1 (-4/5)) = tan θ
Therefore, tan θ = 4/3
However, since sin θ and tan θ are only negative in the fourth quarter;
Therefore, tan θ = (-4/3)
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The partial pressure of CO in a home with air containing 6.2 ppm CO, when the total air pressure is 695 torr, can be calculated by (6.2 ÷ 1,000,000) x 695, which equals 4.3 x 10^-3 torr.
The partial pressure of a gas is the individual pressure contribution a single type of gas makes to the overall pressure of a gas mixture. In this case, a sample of air from a home was found to contain 6.2 parts per million (ppm) of carbon monoxide (CO). To calculate the actual pressure of CO in the room, we can use the fact that 1 ppm = 1 part of the substance per 1,000,000 parts of air.
To do so, we need to multiply thetotal pressure of the air, which is 695 torr, by the ratio of the CO to the total volume of the air. That would be: (6.2 ÷ 1,000,000) x 695 = 4.3 x 10-3 torr. Hence, that is how 4.3 x 10-3 is derived as the partial pressure of CO in this context.
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