43%×64%÷3+86×18=what?
Answers
Answer:
1548.09173333
Answer:
43%×64%÷3+86×18=
1548.09173333
Step-by-step explanation:
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To find the vertical asymptotic equations of the rational function, we must first find the points of intersection of the function with the x-axis. These points are the solutions of the equation f(x) = 0. We decompose the exponential function into the product of two expressions: f(x) = (x² + 9x)(x² - 2x - 15) Now we can set each of the expressions inside the parentheses equal to zero and solve the vertical asymptotic equations: x² + 9x = 0 or x² - 2x - 15 = 0 To solve the first equation, we can factor x out: x(x + 9) = 0 So the two vertical asymptote equations are x = 0 and x + 9 = 0 (that is, x = -9). To solve the second equation, we can use the analysis method or the quadratic formula. Using the analysis method, we can decompose the expression x² - 2x - 15 in the following form: (x - 5)(x + 3) = 0 Therefore, two vertical asymptote equations equal to x - 5 = 0 (that is, x = 5) and x + 3 = 0 (that is, x = -3). So the vertical asymptotic equations of the rational function f(x) = (x² + 9x)(x² - 2x - 15) are equal to x = 0, x = -9, x = 5 and x = -3.
Answers
The median increases and the mean stays the same.
B.
The mean and the median increase by the same amount.
C.
The mean increases more than the median increases.
D.
The mean increases and the median stays the same.
Answers
Answers
4 (t2-4) / 8 / t-2/6
4 (t-2) (t + 2) / 8 / t-2/6
We now use the double C:
24 (t-2) (t + 2) / 8 * (t-2)
We simplify similar terms:
24 (t + 2) / 8
3 (t + 2)
Answer:
The simplified expression is:
3 (t + 2)
Answers
Answer:
Sun is cm away from alpha century.
Sun is m.
Sun is 1.391016 time the size of an atom at this scale.
Step-by-step explanation:
Light year is a measure of distance. It is the distance light travels in an year.
Light year = km
So 4.4 light years = km
km
Lets scale this down to the level of
km
= km
Change the units to centimeters:
cm
= cm
= cm
Therefore on the new scale sun is cm away from alpha century.
Diameter of the sun is 1.391016 million km
Lets change Sun's diameter to the new scale:
km
=km
Lets change kilometers in to meters:
m
=m
Therefore, sun is m
and an atom is
Therefore the sun is 1.391016 time the size of an atom at this scale.
Final answer:
On a 1-to-10^19 scale, the distance from the Sun to the Alpha Centauri is about 44 cm. On this same scale, the Sun itself would have a diameter of about 150 picometers, which is larger than a typical atom.
Explanation:
The 1-to-10^19 scale means for every actual meter in space, we represent 10^19 meters on our model. The Alpha Centauri is 4.4 light-years away from the sun. Considering 1 light-year equals to approximately 9.46x10^15 meters, the real distance from the sun to Alpha Centauri is about 4.16x10^16 meters. So, on the scale, this is about 0.44 meters or 44 cm.
The Sun's real size, with a diameter of 1.5 million kilometers or 1.5x10^9 meters, is represented as 1.5x10^-10 meters or 150 picometers on the scale. This is much bigger than an actual atom, which has a diameter of 0.1 to 0.5 nanometers or 100 to 500 picometers. Hence, on this scale, the Sun would be larger than a typical atom.
Learn more about Scale Representation here:
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Answers
Answer:
The equation is y = 4x+3
Step-by-step explanation:
The slope intercept form of a line is
y = mx+b where m is the slope and b is the y intercept
y = 4x + b
Substitute the x and y value into the equation
7 = 4(1)+b
7 = 4+b
Subtract 4
7-4 =b
3=b
The equation is y = 4x+3
Answer:
y = 4x + 3
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Here m = 4, thus
y = 4x + c ← is the partial equation
To find c substitute (1, 7) into the partial equation
7 = 4 + c ⇒ c = 7 - 4 = 3
y = 4x + 3 ← equation of line