Let's explore possible case scenarios.
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Case A) Each person gets a rose and a daisy (2 flowers per person)
In this case, Jackie can make 2 such arrangements because she has 2 roses. We have 2 left over daisies.
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Case B) Each person gets a rose only (1 flower per person)
Only two arrangements are possible for the same reason as case A. In this situation, we have 4 left over daisies.
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Case C) Each person gets a daisy only (1 flower per person)
We have 4 arrangements possible because we have 4 daisies. The left over flowers are the 2 roses.
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Case D) Each person gets 2 roses
Only one such arrangement is possible, so this only applies to one person really. You can say that 2/2 = 1. We have 4 left over daisies in this case.
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Case E) Each person gets 2 daisies
Since 4/2 = 2, this means we can make 2 arrangements. There are 2 left over roses.
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Case F) Each person gets 2 daisies and 1 rose
We can see that 4/2 = 2 and 2/2 = 1, meaning that we can make at most 2 arrangements here. There are no leftovers. In contrast, the other cases do have leftovers of some kind.
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In short, you can do trial and error to see which case works to fit the conditions your teacher set. Case F is what we go for to have each flower bouquet consist of 2 daisies and 1 rose. We'll get 2 bouquets possible. Notice how cases A through E have at least one left over flower (either of one kind or both types), while case F has no leftovers.
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Approximately how many red candies will be in the packages?
Answer:
5
Step-by-step explanation:
Among the 20 digits shown, each digit appears in the list twice except 0 and 1 appear 3 times and 6 and 9 appear once. That means ...
So, if 1 and 2 represent red candies, there are 3+2 = 5 red candies in the simulated random sample of 20 candies.
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Comment on the question
The simulation makes sense only if it represents taking a single candy from each of 20 packages (of unknown quantity of candies). That is, it seems we cannot answer the question, "how many red candies will be in the packages?" We can only answer the question, "how many of the simulated candies are red?"
Answer:
5
This is the correct answer! I just took the test! Good luck!
an = 3 * 2^n-1
What is the 9th term?
Answer:
a9=3×2^9-1
a9=3×2^8
a9=3×256
a9=768
b) he z-statistic is 1.68, so the null hypothesis cannot be rejected.
c) The z-statistic is 1.85, so the null hypothesis should be rejected.
d) The z-statistic is 4.6, so the null hypothesis should be rejected.
Answer:
its B
Step-by-step explanation:
The squareroot of a negative number is notdefined in the realm of real numbers.
We have,
The squareroot of a negative number is not defined in the realm of real numbers.
The square root function is only defined for non-negative real numbers.
In this case, the expression "negative 9 squared" means the square of negative 9, which is positive 81.
However, taking the square root of the negative of positive 81 would involve imaginary numbers.
If we consider the square root of -81 in the realm of complex numbers, it can be represented as ±9i, where i is the imaginary unit (√-1).
Thus,
The squareroot of a negative number is not defined in the realm of real numbers.
Learn more about imaginarynumbers here:
#SPJ6
С
17
E
A. True
B. False