Answer:
Step-by-step explanation:
a) 7² + a⁰ = 7*7 + 1 = 49 + 1 = 50
Anything raised to 0 is 1 {Eg: 15⁰ = 1 ,(-k)⁰ = 1}
b) 4³ - 3¹ = 4*4*4 - 3 = 64 - 3 = 61
c) 12x⁶ * 7x⁸ = (12*7)*x⁶⁺⁸ = 84x¹⁴
In exponent multiplication, If x is a rational number and a & b are two integers, then xᵃ * xᵇ = xᵃ⁺ᵇ
d) 49a¹³ ÷ 7a⁸ = (49 ÷ 7) * a¹³⁻⁸ = 7a⁵
In exponent division, If x is a rational number and a & b are two integers, then xᵃ ÷ xᵇ = xᵃ⁻ᵇ
e) (2y³)⁵ = 2⁵*(y³)⁵ = 32y³ˣ⁵ = 32y¹⁵
b. 74
c. 81
d. 145
Answer:
44.4
Step-by-step explanation:
it is a right angled triangle so
with reference angle x
perpendicular (p) = 7
hypotenuse (h) = 10
so Now
sin x = p/h
sin x = 7 / 10
x = sin^-1( 7/ 10)
x = 44.42°
Rounding to nearest tenth
= 44.4°
Answer:
7.1
Step-by-step explanation:
you use the Pythagorean theorem to solve this problem. a^2+b^2=c^2.
you are finding value of b plug the variables in = 7^2+b^2=10^2
=49+b^2=100
subtract 49 from both sides
b^2=51
Square root of 51 =7.141 round to nearest tenth =7.1
Answer:
6<x<30
Step-by-step explanation:
x is between x and 30
greater than 6 but less than 30
I hope it helps!
Answer:
its 6 I just took the assignment
Answer:
D, 4
Step-by-step explanation:
The graph crosses the x-axis 4 different times
The number of ways the train could be made up are 4,151,347,200.
A permutation of a set is an arrangement of its members into a sequence or linear order, or if the set is already ordered, a rearrangement of its elements.
Now the given cars are 6 flatcars, 7 boxcars, and 3 livestock cars.
So the total number of cars, n = 6 + 7 + 3
= 16
Now, a train is made up of 9 cars,
Therefore, r = 9
Hence the required number of ways the train could be made is nPr
nPr = n!/(n-r)!
nPr = 16!/(16-9)!
nPr = 16!/7!
nPr = 16*15*14*13*12*11*10*9*8
nPr = 4,151,347,200
Hence,the number of ways the train could be made up are 4,151,347,200.
More about Permutation :
#SPJ2
Answer:
The answer is A on edge
Step-by-step explanation: