For this line 3x−4y−12=0, which statement is true? 1- The x-intercept is 4, and the y-intercept is 3. 2-The x-intercept is 4, and the y-intercept is -3 3-The x-intercept is 3, and the y-intercept is -4. 4-The x-intercept is 3, and the y-intercept is 4.

Answers

Answer 1

Answer:

9514 1404 393

Answer:

2. The x-intercept is 4, and the y-intercept is -3

Step-by-step explanation:

The given equation is in general form. I find it easier to see the intercepts when the equation is written in standard form:

3x -4y = 12

Setting y=0 and solving for x, we have the x-intercept:

3x = 12 ⇒ x = 12/3 = 4

Setting x=0 and solving for y, we have the y-intercept:

-4y = 12 ⇒ y = 12/-4 = -3

The x-intercept is 4; the y-intercept is -3.

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If given f(x)=2x+5 what is f(-10)

Answers

To solve input -10 into x to get your answer, it should look something like this (f(-10) = 2(-10) + 5

How do u solve this equation help me

Answers

In this equation P=1

The first answer is right, but the working goes like this:
-p - 10 = -11
+ p
-10 = -11 + p
+ 11
1 = p

...........................

Answers

Answer:

b) b√a

Step-by-step explanation:

Given equation,

→ ab²

Then the square root of ab² is,

→ square root of ab²

→ √(ab²)

→ b√a

Hence, option (b) is the answer.

Answer:

B) b√a

Step-by-step explanation:

b√a

Driving along, terry notices that the last four digits on his car's odometer are palindromic. a mile later, the last five digits are palindromic. after driving another mile, the middle four digits are palindromic. one more mile, and all six are palindromic. what was the odometer reading when terry first looked at it? form a linear system of equations that expresses the requirements of this puzzle.

Answers

Designate the initial digits, left to right, as {a, b, c, d, d, c}.

After adding one mile, the digits are {a, b, c, d, c, b}, so the relevant equation is
10c +b = 10d +c +1

After adding another mile, the digits are {a, b, c, c, b, e}, so the relevant equation is
100c +10b +e = 100d +10c +b +1

After another mile, the digits are {a, b, c, c, b, a}, so the relevant equation is
a = e +1

In summary, we have 3 equations in 5 unknowns.
b + 9c -10d = 1
9b +90c -100d +e = 1
a - e = 1
along with the constraints {a, b, c, d, e} ∈ {0, ..., 9}

_____
These have the solution {a, b, c, d, e} = {1, 9, 8, 8, 0}, so the odometer readings were
198888
198889
198890
198891

An independent random sample is selected from an approximately normal population with unknown standard deviation. Find the degrees of freedom and the critical t-value for the given sample size and confidence level.(a) n = 6, CL = 90%(b) n = 21, CL = 98%(c) n = 29, CL = 95%(d) n = 12, CL = 99%

Answers

(a) For n = 6, CL = 90%,

The degrees of freedom: 5, Critical t-value: 2.571

(b) For n = 21, CL = 98%,

The degrees of freedom: 20, Critical t-value: 2.845

The degrees of freedom: 28, Critical t-value: 2.048

(d) For n = 12, CL = 99%,

The degrees of freedom: 11, Critical t-value: 3.106

Use the concept of critical t- value defined as:

A critical value is a number that is used in hypothesis testing to compare to a test statistic and evaluate whether or not the null hypothesis should be rejected. The null hypothesis cannot be rejected if the test statistic's value is less extreme than the crucial value.

(a) Given that,

n = 6 and a confidence level of 90%,

The degrees of freedom are,

n-1 = 6-1

The degrees of freedom = 5.

To find the critical t-value,

Look it up in the t-distribution table using a confidence level of 90% and a degree of freedom of 5.

From the table,

The critical t-value is approximately 2.571.

(b) Given that,

n = 21 and a confidence level of 98%,

The degrees of freedom are,

n-1 = 21-1

The degrees of freedom = 20.

By referring to the t-distribution table with a confidence level of 98% and degrees of freedom of 20,

The critical t-value is approximately 2.845.

n = 29 and a confidence level of 95%,

The degrees of freedom are,

n-1 = 29-1

The degrees of freedom = 28

Using the t-distribution table with a confidence level of 95% and degrees of freedom of 28,

The critical t-value is approximately 2.048.

(d) Given that,

n = 12 and a confidence level of 99%,

The degrees of freedom are,

n-1 = 12-1

The degrees of freedom = 11

By consulting the t-distribution table with a confidence level of 99% and degrees of freedom of 11,

The critical t-value is approximately 3.106.

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Final answer:

To find the degrees of freedom and critical t-value for each given sample size and confidence level, we can use the t-distribution and a t-table. The degrees of freedom (df) for each sample is equal to the sample size minus 1. The critical t-value can be found using the t-table with the corresponding degrees of freedom and the confidence level.

Explanation:

To find the degrees of freedom and critical t-value for each given sample size and confidence level, we can use the t-distribution and a t-table. The degrees of freedom (df) for each sample is equal to the sample size minus 1. For example, for (a) n = 6, df = 6 - 1 = 5. The critical t-value can be found using the t-table with the corresponding degrees of freedom and the confidence level.

For (a) n = 6, CL = 90%, the critical t-value is approximately 1.943.

For (b) n = 21, CL = 98%, the critical t-value is approximately 2.861.

For (c) n = 29, CL = 95%, the critical t-value is approximately 2.045.

For (d) n = 12, CL = 99%, the critical t-value is approximately 3.106.

Learn more about Finding degrees of freedom and critical t-values for given sample sizes and confidence levels here:

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If a function is defined by the formula y=1/2x + 3 and its domain is given by the set {-4,0,8}, then which of the following sets gives the function's range?

Answers

Answer:

y = {1, 3, 7}

Step-by-step explanation:

Given

y = ½x + 3

Domain: {-4, 0, 8}

Required

Determine the range of the function

To do this, we simply substitute each value of the domain in the given expression

We start with the first

Substitute -4 for x in y = ½x + 3

y = ½ * -4 + 3

y = -2 + 3

y = 1

Then 0

Substitute 0 for x in y = ½x + 3

y = ½ * 0 + 3

y = 0 + 3

y = 3

Lastly, 8

Substitute 8 for x in y = ½x + 3

y = ½ * 8 + 3

y = 4 + 3

y = 7

Hence, the range of the function is:

y = {1, 3, 7}

Answer:1,3,7

Step-by-step explanation:

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