Answer:
6825 in
Step-by-step explanation:
Since the shape is a composite figure, we need to break it up into 2 shapes!
Rectangle and a triangular prism
Solving for Rectangle...
Volume = Length · Width · Height
Volume = 30 · 13 · 13
Volume = 5070 in
Solving for Triangular Prism
Volume = Length · Width · Height / 2
Volume = 30 · 9 · 13 / 2
Volume = 3510/2
Volume = 1755 in
Finally, add the volumes!
5070 + 1755 = 6825 in
20x2 – 12x + 30x – 18
6x3 + 14x2 – 12x – 28
8x3 + 20x2 + 3x + 12
11x4 + 4x2 – 6x2 – 16
Prime polynomials are those polynomials that are not factored into lower degree polynomial. The options that are prime polynomials are 1), 4), and 5).
Evaluate all options in order to check that the polynomials are prime or not:
1).
5x(3x + 2) - (9x - 7)
So, this polynomial can not be factored into lower degree polynomial. Therefore, it is a prime polynomial.
2).
(4x + 6)(5x - 3)
So, this polynomial is converted into a lower degree polynomial. Therefore, it is not a prime polynomial.
3).
So, this polynomial is converted into a lower degree polynomial. Therefore, it is not a prime polynomial.
4).
So, this polynomial can not be factored into lower degree polynomial. Therefore, it is a prime polynomial.
5).
So, this polynomial can not be factored into lower degree polynomial. Therefore, it is a prime polynomial.
For more information, refer to the link given below:
Answer:
The prime polynomials are 1, 4 and 5
Step-by-step explanation:
Given some polynomials we have to classify the polynomials prime or not.
Prime polynomials are the polynomial with integer coefficients that cannot be factored into lower degree polynomials.
⇒
can't be factored into lower degree polynomial ∴ prime polynomial.
⇒
⇒
hence, not a prime polynomial.
⇒
⇒
hence, not a prime polynomial.
⇒
can't be factored into lower degree polynomial ∴ prime polynomial.
⇒
can't be factored into lower degree polynomial ∴ prime polynomial.
The prime polynomials are 1, 4 and 5
So answer is C.
Hmm first I'll check the slanted line cutting 2nd quardrant..
some points on this line are (-3,0),(0,3),(2,5),(3,6),etc.
Testing (-3,0)=(x,y):
y=-3+3=0 (true)..comparable with y=x+3
Testing (2,5)=(x,y):
y=2+3=5 (true)..comparable with y=x+3
Since this line bounds the value within some limits less than or equal to x+3(see graph you can see it clearly)...so it can be represented by y<=x+3.
Similarly for next line cutting 1st and 4th quardrant,
Points: (0,-4),(1,-1),(2,2),etc..
Testing (0,-4)=(x,y):
y=3*0-4=-4(true)...comparable with y=3x-4
Testing (1,-1)=(x,y):
y=3*1-4=-1(true)...comparable with y=3x-4
This line bounds within the region y>3x-4
NOTE:
1)If the region is bounded by solid line(line without dot) then you write inequality as y<=something or y>= something.
2)If the region is bounded by dotted line(line withdot) then you write inequality as y<something or y> something.
Hope this helps!
Answer:
15:20=3:4
Step-by-step explanation:
6x - 15 = -3y
2) 6y + 2x = 8
12y + 4x = 4
The correct classification of the given equations is as follows:
This refers to the system of equations where an equation has infinite solutions and has more than one form on a given line.
With this in mind, we can see that when we are given a system of equations such as
5 - y = 2x
6x - 15 = -3y, then we know that this is a dependent equation because of the infinite solutions on the two equations.
Read more about dependent equations here:
brainly.com/question/10417850
(10/12)(100) = (5/6)(100) = 83.3% not cracked
The points in the preimage lie in the same plane as the points in the image.
All the points in the preimage are shifted the same distance.
The orientation of sequences of points in the preimage are always preserved.
Answer with explanation:
There are four kind of Rigid transformation that can take place in a two dimensional or Three dimensional geometrical Shape
1. Rotation
2. Reflection
3.Dilation
4. Translation
When we translate a geometrical shape , the Preimage , shifts from one position to another position in the plane in which it lies ,without changing the shape ,size ,and Interior angle of the PreImage.
→→I have described first three properties ,which are true to translation by taking a triangle ,having vertices , (0,0), (0,1) and (1,0).
Now, translating the triangle , by 1 unit right and 1 unit up,got the triangle having vertices, (1,1),(1,2) and (2,1).
Option 4 : The orientation of sequences of points in the pre image are always preserved, is the property of a rigid transformation that appears exclusive to translations.