MATHEMATICS HIGH SCHOOL

On the distant planet Cowabunga, the weights of cows have a normal distribution with a mean of 483 pounds and a standard deviation of 70 pounds. The cow transport truck holds 5 cows and can hold a maximum weight of 2840. If 5 cows are randomly selected from the very large herd to go on the truck, what is the probability their total weight will be over the maximum allowed of 2840

Answers

Answer 1

Answer:

Answer: 0.0033

Step-by-step explanation:

Let x be a random variable that denotes the weights of cows.

Given: $\mu = 483,\ \sigma=70$

maximum weight can be hold= 2840 pounds.

Mean weight = $(2840)/(5)$ = 568 pounds

The probability their total weight will be over the maximum allowed of 2840

= $P(X>2840)$

$P((x-\mu)/((\sigma)/(√(n)))>(568-483)/((70)/(√(5))))\n\n=P(z>2.715)\n\n=1-P(z<2.715)\n\n=1-0.9967=0.0033$

Hence, the required probability = 0.0033

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Marsha gave the cashier $20 to pay for 3 pairs of socks. The Cashier gave her $5.03 in change . Each pair of socks cost the same amount.What is the cost in dollars and cents for each pair of socks? ____ $

Answers

First, you must subtract.

$20 - $5.03 = $14.97This is because he recieved $5.03 in exchange.

Next, you must divide by 3.

$14.97 / 3 = $4.99

Therefore each pair of socks costs $4.99.

Hope this helps! Have a good day/night! c:

If you put $150 in a savings account that paid 6% compounded monthly, how much interest would you earn in five years?

Answers

Answer:

Step-by-step explana8tion:

80$ with that 6%

Let me figure it out

Solve logarithm equation please with steps.

Answers

The first time I did it, I got an answer that's not one of the choices. The second time
I did it, I got an answer that IS . Here are both of my procedures. If all you want is
the answer, look down below at the second one. But if you could help me out, now
that you know how to do this stuff, please look at my first solution and tell me where
I messed up. I can't find it.
=======================================================

Here's what the problem tells you:

D = 10 log ( ' I ' / 10⁻¹² )

D = 60 . . . . . find ' I ' .

Here we go:

60 = 10 log ( ' I ' / 10⁻¹² )

Divide each side by 10 :

6 = log ( ' I ' / 10⁻¹² )

Raise 10 to the power of each side of the equation:

10⁶ = ' I ' / 10⁻¹²

Multiply each side by 10¹² :

10¹⁸ = ' I '     That's 10^18. It looks bad, because that isn't one of the choices.

Let's try a slightly different procedure:

============================================

After substituting 10⁺¹² for I₀ , we're working with this formula:

   D = 10 log ( 'I' / 10⁺¹² )

Let's just look at the log part of that.

The log of a fraction is [ log(numerator) - log(denominator) ]

log of this fraction is [ log( 'I' ) - log(10⁻¹²) ]

But log(10⁻¹²) is just (-12) .

So the log of the fraction is [ log( 'I' ) + 12 ]

And the whole formula is now:

   D = 10 [ log( 'I' ) + 12 ]

60 = 10 [ log( 'I' ) + 12 ]

Divide each side by 10 :

6 = log( 'I' ) + 12

Subtract 12 from each side :

-6 = log ( ' I ' )

' I ' = 10⁻⁶

That's choice-'B' .

==================================================

I'm going to leave the first solution up there, in hopes that you, or one
of the many aces, experts, and geniuses that prowl this site constantly,
can weigh in and show me my blunder on the first attempt.

Carlos owns an orchard. His apple trees produced 315 bushels of apples. Each bushel of apples weighs about 48 pounds. There are about 3 apples in each pound. About how many apples did Carlos' apple trees produce? Please show how it is done. Thank you