Answer:
1 month
Step-by-step explanation:
249 is the amount she spends for buying the kitten, (299-50=249) which she only has to pay once.
20 is the amount she has to spend every month, the rate of change.
The problem can be modeled with the general equation:
y = 20x + 249
In this equation, x the the time in months and y is the amount of money spent.
Substitute 250 for y.
y = 20x + 249
250 = 20x + 249 <= isolate x to get the number of months
1 = 20x
x = 1/20
Carol will only spent money every month, not for 1/20 of a month.
It will only take Carol 1 month to spent $250.
Check answer:
Substitute x for 1
y = 20x + 249
y = 20(1) + 249
y = 269
269 is more than 250 already.
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The value of the given expression is 20.
An expression in math is a sentence with a minimum of two numbers or variables and at least one math operation. This math operation can be addition, subtraction, multiplication, or division.
Given that, h=4 and j=6 we need to find hj-h
hj-h
put h=4 and j=6
4 x 6 - 4
= 24 - 4
= 20
Hence, the required value is 20.
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Step-by-step explanation:
as I can see this the answer is
x = 25/78
in decimal
x = 0.320
The problem involves joint variation with variables y, x, and z. After finding the constant of variation, we substitute the given values into the joint variation equation and determine that x = 16.67
First, we establish the equation of joint variation, which in this context is y = kxz, where 'k' is the constant of variation. When y=13, x=26, and z=6, we insert these values into the equation to solve for 'k'. This gives us k = y/(xz) = 13/(26*6) = 0.08333.
Now that we have the constant 'k', we can find the value of 'x' when y=25 and z=18. We rearrange our equation to solve for 'x', resulting in x = y/(kz). Substituting the known values, we get x = 25/(0.08333*18) = 25/1.5 = 16.67. Therefore, if y varies jointly with x and z, and y=25 when z=18, then x = 16.67.
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