Answer:
a=6
Step-by-step explanation:
Since this is a right triangle, we can use the Pythagorean theorem
a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse
a^2 + 8^2 = 10^2
a^2 + 64= 100
a^2 +64-64 = 100-64
a^2 = 36
Take the square root of each side
sqrt(a^2) = sqrt(36)
a = 6
Answer:
a = 6
Step-by-step explanation:
According to the question,
Using Pythagorean theorem
( a )² + ( b )² = ( c )²
( a )² + ( 8 )² = ( 10 )²
evaluate the exponent
a ² + 64 = 100
subtract 64 from each side
a ² + 64 - 64 = 100 - 64
a ² = 36
Take the square root of each side
√a² = √36
a = 6
1/2x - 3y = 8
Answer:
$38.46
Step-by-step explanation:
It is given that the price of a pair of trousers was decreased by 22% to $30.
Let $x be the original price of the trousers.
22% less of original price is equal to $30.
Divide both sides by 0.78.
Therefore, the original price of the trousers is $38.46.
Answer:
12
Step-by-step explanation:
When you multiply both sides of the equation you are multiplying them by the common denominator. In this case, the common denominator is 12. So multiply, then you have the most simplified problem of 2x=9x-8.
The Box with a smaller base has a height that is 4 times taller than the Box having a larger base.
We know the volume of a cuboid is the product of its length, breadth, and height or v = l×b×h.
Given, we have two boxes let us denote them by B₁ and B₂ and their respective heights are h₁ and h₂.
To obtain how many times one box is relative to the other we have to equate their respective volumes.
Given, one box has a base that is 10cm by 10 cm and another box has a base that is 5cm by 5cm.
∴ 5×5×h₁ = 10×10×h₂.
25h₁ = 100h₂.
h₁ = 4h₂.
So, h₁ is 4 times taller than h₂.
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Answer:
x=4
Step-by-step explanation:
5^2X=10^2X
25X=10X
2X=100/25
x2(x + 9) – 5(x + 9)
x(x2 + 5) – 9(x2 + 5)
x(x2 – 5) – 9(x2 – 5)
The answer choice which shows a way to determine the factors by grouping is; x(x² + 5)–9(x² + 5).
According to the task content, the factors of the expression are to be determined by grouping.
On this note, one way to group the factors would be;
x³ + 5x - 9x² -45
Upon factorisation;
x(x² + 5) – 9(x² + 5).
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