MATHEMATICS HIGH SCHOOL

What is the 6th term of the geometric sequence?3,6, 12, 24, ...
A. 36
B. 27
C. 48
O D. 96
What is the 6th term of the geometric sequence? 3,6, - 1

Answers

Answer 1
Answer:

Answer:

96 is the 6th term of the geometric sequence

Step-by-step explanation:

The sequence is just adding the number twice to get the nect sequence.

So,

3+3 = 6

6+6 = 12

12+12 = 24

24+24 = 48

48+48 = 96   this is the 6th term

Hope this is helpful

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What is 9x^2-24x+ 16

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9X^2-24X+16=(3X-4)(3X-4)=(3X-4)^2

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Jane is given this sequence and is asked to write the definition. Which definition describes the sequence.

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A particular order in which related events, movements, or things follow each other. Hope this helped.
a particular order in which related events, movements, or things follow each other. hope this helps and may i have brainliest 

If y=3c+2, find the value of y when x=-3

Answers


There may be a relationship between 'x' and 'y', but we have no equation
that shows what it is.  So we don't have the information we need to answer
the question.

A recent study indicates that the annual cost of maintaining and repairing a car in a town in Ontario averages 200 with a variance of 260. A tax of 20% is introduced on all items associated with the maintenance and repair of cars (i.e., everything is made 20% more expensive). Calculate the variance of the annual cost of maintaining and repairing a car after the tax is introduced.

Answers

Answer:

374.4

Step-by-step explanation:

All items related to the maintenance are 20% more expensive, it means that each datum is 20% bigger including the average.

The variance its a dispersion measurof the data and its calculated of this way:

\sigma^(2) =(1)/(n) \sum\limits^n_(i=1) (x_(i)-\var{x})^2\n

Here n is the number of data, \var{x} is the average and x_(i) represent each datum. The increment in 20% in each parameter can be represented multiplying for 1.2, of this way

\sigma_(20\%)^(2) =(1)/(n) \sum\limits^n_(i=1) (1.2x_(i)-1.2\var{x})^2\n

Factorizing the 1.2 we have:

\sigma_(20\%)^(2) =(1)/(n) \sum\limits^n_(i=1) (1.2(x_(i)-\var{x}))^2

\sigma_(20\%)^(2) =(1)/(n) \sum\limits^n_(i=1)1.2^(2) (x_(i)-\var{x})^2

\sigma_(20\%)^(2) =(1.2^(2))/(n) \sum\limits^n_(i=1) (x_(i)-\var{x})^2\n

That is:

1.2^(2)\sigma^(2)=\sigma_(20\%)^(2)

The new variance is 1.2^(2) \sigma^(2) =1.44*260=374.4

Final answer:

To calculate the variance of the annual cost of maintaining and repairing a car after the tax is introduced, we can use the formula var(X + c) = var(X), where X is the original cost and c is the tax rate. In this case, the tax rate is 20%, so c = 0.2. The variance of the original cost is 260, so the variance of the cost after the tax is introduced is also 260.

Explanation:

To calculate the variance of the annual cost of maintaining and repairing a car after the tax is introduced, we can use the formula var(X + c) = var(X), where X is the original cost and c is the tax rate. In this case, the tax rate is 20%, so c = 0.2. The variance of the original cost is 260, so the variance of the cost after the tax is introduced is also 260.

Learn more about variance of annual cost here:

brainly.com/question/34041296

#SPJ12

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f(x)=4 x^(3)+a x^(2) +bx+c and there is a local min at x=-1 and an inflection point at x=-2. Find the values of a and b

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