Which equation is equivalent to 4 x = t + 2
s = t-2
s=4/t+2
s=t+2/4
s=t+6

Answers

Answer 1

Answer: B= S=4/t+2
whenever you have the equation 4 x = t+2 you are trying to isolate the X by doing that you have ti take the 4 and divide it to the other side so the x can stay on that side

Related Questions

Which scatterplot shows the weakest positive linear association?On a graph, points are grouped closely together and increase.On a graph, points are grouped closely together to form a line and increase.On a graph, points are grouped closely together and decrease.On a graph, points are grouped closely together to form a line and decrease.
4. Tori bought x shares of Mattel stock for m dollars per share. She soldall of the shares months later for y dollars per share. Express her cap- ital gain or loss algebraically.
Simplify by using factoring: (2a+6b)(6b−2a)−(2a+6b)^2
Kelly flies a distance of 2,100 miles. the trip takes 4 2/3 hourswhat is the airplanes unit rate of speed in miles per hour?at this rate of speed, how many miles the airplane travel in 1 1/2 hours?
An office building loses a third of its heat between sundown and midnight and an additional half of the original amount of heat between midnight and 4 AM. If five-eighths of the remaining heat is lost between 4 AM and 5 AM, what proportion of the total heat loss occurs between 5 AM and sunrise?

3n-5=-8(6+5n) in distributive property

Answers

Using distributive property we can expand the expression as

3n - 5 = -8 x 6 + (-8) x 5n

To apply the distributive property to the equation

3n - 5 = -8(6 + 5n), we need to distribute the -8 to the terms inside the parentheses.

Using the distributive property, we have:

3n - 5 = -8 x 6 + (-8) x 5n

Simplifying further:

3n - 5 = -48 - 40n

Now, we can continue solving the equation using the simplified form as

3n + 40n = -48 + 5

43n = -43

n= -1.

Learn more about distributive property here:

brainly.com/question/30321732

#SPJ6

Answer:

n=-1

Step-by-step explanation:

3n-5=-8(6+5n)

3n-5=-48-40n

add 40n to both sides

43n-5=-48

n=-1

A survey in Men’s Health magazine reported that 39% of cardiologists said that they took vitamin E supplements. To see if this is still true, a researcher randomly selected 100 cardiologists and found that 36 said that they took vitamin E supplements. At α = 0.05, test the claim that 39% of the cardiologists took vitamin E supplements. A recent study said that taking too much vitamin e might be harmful how might this study make the results of the previous study invalid?

Answers

Answer:

$z=\frac{0.36 -0.39}{\sqrt{(0.39(1-0.39))/(100)}}=-0.615$

The p value for this case would be:

$p_v =2*P(z<-0.615)=0.539$

For this case since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true proportion is not different from 0.39

Step-by-step explanation:

Information given

n=100 represent the random sample taken

X=36 represent the number of people that take E supplement

$\hat p=(36)/(100)=0.36$ estimated proportion of people who take R supplement

$p_o=0.39$ is the value that we want to test

$\alpha=0.05$ represent the significance level

z would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the true proportion is equatl to 0.39 or not, the system of hypothesis are.:

Null hypothesis: $p=0.39$

Alternative hypothesis: $p \neq 0.39$

The statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{(p_o (1-p_o))/(n)}}$ (1)

Replacing the info we got:

$z=\frac{0.36 -0.39}{\sqrt{(0.39(1-0.39))/(100)}}=-0.615$

The p value for this case would be:

$p_v =2*P(z<-0.615)=0.539$

Literally have no clue how to do the heart beat please help

Answers

Step-by-step explanation:

To find the rate, divide the number of heartbeats by the number of seconds.

You: 22 beats / 20 seconds = 1.1 beats per second.

Friend: 18 beats / 15 seconds = 1.2 beats per second.

6. Find the values of x and y.

Answers

Answer:

x= 17 radical 3

y= 34

Step-by-step explanation:

30-60-90 triangle rule

MATHAnswer and I will give you brainiliest
Answer and I will give you brainiliest

Answers

Answer:

I don't now this but you should do pemdas that really helped me

Step-by-step explanation:

The first step is perthansies then exponents and then multiplication then division and last addition and subtraction that should give you your answer.

The number of chocolate chips in an 18-ounce bag of chocolate chip cookies is approximately normally distributed with a mean of 1252 chips and standard deviation 129 chips.(a) What is the probability that a randomly selected bag contains between 1000 and 1500 chocolate chips, inclusive? (b) What is the probability that a randomly selected bag contains fewer than 1025 chocolate chips? (c) What proportion of bags contains more than 1200 chocolate chips? (d) What is the percentile rank of a bag that contains 1425 chocolate chips?

Answers

Using the normal distribution, it is found that:

a) There is a 0.947 = 94.7% probability that a randomly selected bag contains between 1000 and 1500 chocolate chips, inclusive.

b) There is a 0.0392 = 3.92% probability that a randomly selected bag contains fewer than 1025 chocolate chips.

c) 0.3446 = 34.46% of bags contains more than 1200 chocolate chips.

d) The bag is in the 91st percentile.

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = (X - \mu)/(\sigma)$

It measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

Mean of 1252 chips, thus $\mu = 1252$ .
Standard deviation of 129 chips, thus $\sigma = 129$ .

Item a:

The probability is the p-value of Z when X = 1500 subtracted by the p-value of Z when X = 1000, thus:

X = 1500:

$Z = (X - \mu)/(\sigma)$

$Z = (1500 - 1252)/(129)$

$Z = 1.92$

$Z = 1.92$ has a p-value of 0.9726.

X = 1000:

$Z = (X - \mu)/(\sigma)$

$Z = (1000 - 1252)/(129)$

$Z = -1.95$

$Z = -1.95$ has a p-value of 0.0256.

Then, 0.9726 - 0.0256 = 0.947

There is a 0.947 = 94.7% probability that a randomly selected bag contains between 1000 and 1500 chocolate chips, inclusive.

Item b:

This probability is the p-value of Z when X = 1025, thus:

$Z = (X - \mu)/(\sigma)$

$Z = (1025 - 1252)/(129)$

$Z = -1.76$

$Z = -1.76$ has a p-value of 0.0392.

There is a 0.0392 = 3.92% probability that a randomly selected bag contains fewer than 1025 chocolate chips.

Item c:

This proportion is 1 subtracted by the p-value of Z when X = 1200, thus:

$Z = (X - \mu)/(\sigma)$

$Z = (1200 - 1252)/(129)$

$Z = -0.4$

$Z = -0.4$ has a p-value of 0.3446.

0.3446 = 34.46% of bags contains more than 1200 chocolate chips.

Item d:

This percentile is the p-value of Z when X = 1425, thus:

$Z = (X - \mu)/(\sigma)$

$Z = (1425 - 1252)/(129)$

$Z = 1.34$

$Z = 1.34$ has a p-value of 0.91.

The bag is in the 91st percentile.

A similar problem is given at brainly.com/question/13680644

Final answer:

The probability and percentiles can be found using the z-score formula and then looking these z-scores up in the standard normal distribution table.

Explanation:

In this question, we're dealing with a normal distribution. For a normal distribution, probabilities can be calculated using the z-score formula which is given by Z = (X - μ) / σ, where X is the value from which you want to find the probability, μ is the mean and σ is the standard deviation.

(a) To find the probability that a randomly selected bag has between 1000 and 1500 chocolate chips, we need to find the z-scores for both 1000 and 1500 and then find the area between these two z-scores in the standard normal distribution table. (b) To find the probability that a randomly selected bag has less than 1025 chips, we find the z-score for 1025 and find the area to the left of it in the standard normal distribution table. (c) To find the proportion of bags containing more than 1200 chips, we find the z-score for 1200 and then find the area to the right of it in the standard normal distribution table. (d) Percentile rank can be found by finding the z-score for 1425 chips, and then finding the corresponding percentile in the standard normal distribution table.