Calcular: log 4 2 = (escribir el resultado como decimal)

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Answer 1
Answer:

Answer:

1/2 or 0.5

Step-by-step explanation:


Related Questions

The average (A) of two numbers, m and n, is given by the formula A = m+t/2 . Findthe average of the two numbers 36 and 72. The solution is
Of all postsecondary degrees awarded in the United States, including master's and doctorate degrees, 21% are associate's degrees, 58% are earned by people whose race is White, and 12% are associate's degrees earned by Whites. What is the conditional probability that a degree is earned by a person whose race is White, given that it is an associate's degree
Can someone please help me solve 4 & 5? I'll love you forever
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Jack buys a bag of 5 apples, eachequal in size. He eats of 1/2 of one apple. What fraction of the bag ofapples did he eat?​

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Answers

1877m/min
Just multiple the Miles by the meters, then divide by 60

Simplify each expression below as much as possible. 6x + 2 - 1 - 4x - 3 - 2x + 2

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collect like terms
0+2-1-3+2
calculate the sum or difference
0+0
remove 0

solution: 0

If I wanted the margin of error for the 95% confidence interval to be 1 inch, I should select a simple random sample of size: (assume the population standard deviation = 2.415) A. 5.
B. 7.
C. 23.
D. 39

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We are given with
Confidence interval of 95%. This corresponds to a Z value of 1.96
Margin of error, d = 1 inch
Population standard deviation, σ = 2.415 inch

We can calculate for the sample size using the formula
n = Z² σ² / d²
Substituting,
n = 1.96² (2.415)² / 1²
n = 22.4 ~ 23

The area of a rectangle is at least 115 square centimeters. The width of the rectangle is 5 centimeters and the length of the rectangle is x centimeters. what are the value(s) of x

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the census is 60 because it’s obviously when you divided

Which graph shows an increasing linear function? p.s dont mind the tabs lol!!!

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i believe it’s the bottom left graph

Help! - Answer = Brainliest!

Thanks!

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Answer:

no

Step-by-step explanation:

i copied the person above me :)

sorryyy not sorry lol

#respectfully