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Explanation:
To get the unit cost, we divide the total cost over the number of pounds.
We can do this for any row
You don't need to show all four row calculations. You can simply pick one row.
This tells us that each pound costs $1.75
Put another way: the price is $1.75 per pound
b. Write a rule for the function p(r) that expresses the final price p of a T-shirt with the discount applied and sales tax added.
c. How much would you pay during Bargain Days for a shirt regularly priced at $15.50?
Answer:
A:
Let the regular price of the t shirt be = r
Let the total cost of the t shirt be = t
So, we can say :
B:
C:
Substituting r = 15.50
=>
= $11.025
(4x3+2x+1)÷(x+1)
4x2−4x+6+5x+1
4x2+4x−6−5x+1
4x2−4x+6−5x+1
4x2+4x+6−5x+1
4x2+4x−6−5x+1 is the solution for (4x3+2x+1)÷(x+1)
A division is a process of splitting a specific amount into equal parts.
We need to solve,
(4x3+2x+1)÷(x+1)
We use Synthetic division, Synthetic division is a shorthand method for dividing a polynomial by a linear factor such as x + 3, and it's much simpler and faster.
Step 1: Set up the synthetic division.
Step 2: Bring down the leading coefficient to the bottom row.
Step 3: Multiply by the value just written on the bottom row.
Step 4: Add the column created in step 3.
We get 4x2+4x−6−5x+1.
To learn more on Division click:
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Answer:
Step-by-step explanation:
(4x^3+2x+1)÷(x+1)
Using synthetic division is
4x^2-4x+6- 5/x+1
The graph will show exponential growth.
The graph will appear linear.
The domain will be the set of natural numbers.
The range will be the set of natural numbers.
The graph will show exponential decay.
Answer:
Option 3 and 5 are correct
Step-by-step explanation:
We have given a geometric series 640,160,40,10....
Common ratio of geometric series is
Here our common ratio is less than zero
It will show the graph of exponential decay
Hence, option 5 is correct.
The general term of geometric series is
Domain will be all natural numbers since, geometric series take only natural numbers.
Here, values of "n" is domain
Hence, option 3 is correct.
Range can be any positive real numbers not only natural number
Range is the value of
Hence, option 4 is discarded.
Graph can not be linear of a geometric series being exponential
Hence, option 2 is discarded.
Option 1 is discarded because it is exponential decay function so it can not be exponential growth.
Therefore, Option 3 and 5 are correct.
Answer:
The options that hold true are:
Step-by-step explanation:
We are given a geometric sequence as:
640, 160, 40, 10, ...
Clearly we see that each term is decreasing at a constant rate as compared to it's preceding term.
Hence, the graph formed by this sequence will be a exponential graph with decay .
( since, the terms of the sequence are decreasing)
The sequence could be modeled as:
Let represents the nth term of the sequence.
Hence,
As, the sequence is geometric hence the domain will be a set of natural numbers.
but the range will be positive real numbers.
Hence, the correct option is:
The domain will be the set of natural numbers.
The graph will show exponential decay
The general equation of a circle is . The two options are option(A) and option(E).
There are five options in which five equation of the circle is given.
We have to find the two equations of the circle which have the diameter of 12 units and its center lies on the y-axis.
the general equation of circle having radius of r units and (h,k) as center of circle is given as,
We also know that for the center to lie on y-axis, the value of h becomes 0.
So, the equation will be,
Now, it is clear from all the options that option(A) option(C) and option(E) has radius of 6 units, so neglecting all the other options.
Clearly, in option(c) the center doesn't lie on the y-axis.
so this can't be the required equation.
Therefore, the two options will be option(A) and option(E).
For more details on equation of circle follow the link:
Answer:
(14.7 , 16.9)
Step-by-step explanation:
it is given that tons
σ=3.8 tons
n=49
at 95% confidence level α=1-.95=0.05
=1.96 ( from the standard table)
at 95% confidence level the coefficient interval for μ is
(14.7, 16.9)