Step-by-step explanation:
81/5=3x
x=81×1/5×3
x=81/15
A = 19 units2
A = 17 units2
A = 30 units
A = 18 units2
9514 1404 393
Answer:
(d) A = 18 units²
Step-by-step explanation:
Line CE can be considered to be the base of two triangles. It is 6 units long. The upper triangle is 4 units high, and the lower triangle is 2 units high. The formula for the area of a triangle is ...
A = 1/2bh
Then the sum of the areas of the two triangles is ...
A = 1/2(6)(4) +1/2(6)(2) = 12 +6 = 18
The area of the polygon is 18 square units.
Answer: A=18units2
Step-by-step explanation:
I said 17 before and got it wrong lol.
Next time I said 18 cuz it seemed like the closest when I estimated what it looked like the units it covered, so it's right:)
hope it helps!
2 and 24 are a factor pair of 48 since 2 x 24= 48
3 and 16 are a factor pair of 48 since 3 x 16= 48
4 and 12 are a factor pair of 48 since 4 x 12= 48
6 and 8 are a factor pair of 48 since 6 x 8= 48
8 and 6 are a factor pair of 48 since 8 x 6= 48
12 and 4 are a factor pair of 48 since 12 x 4= 48
16 and 3 are a factor pair of 48 since 16 x 3= 48
24 and 2 are a factor pair of 48 since 24 x 2= 48
48 and 1 are a factor pair of 48 since 48 x 1= 48
Answer:
13.48
Step-by-step explanation:
So I used the Order of Operation and went in order to solve the problem. First is P (Parentheses)
(1.74) = 1.74
Next, Exponents (E).
There are none.
Then, Multiplication and Division (from left to right).
2(1.74) = 3.48 | 15-9+2.65+1.35+3.48.
The fourth is Addition and Subtraction (from left to right).
15-9+2.65+1.35+2= 13.48
Step-by-step explanation:
16. d-4 = -7
or, d = -7+4
or, d = -3
therefore, d = -3.
17. c-34 = 20
or, c = 20+34
or, c = 54
therefore, c = 54
18. a-4 = -18
or, a = -18 + 4
or, a = -14
therefore, a = -14
19. r-3 = 8
or, r = 8+3
or, r = 11
therefore, r = 11
20. z-100 = 100
or, z = 100+100
or, z = 200
therefore, z = 100
21. 5 = d - 1
or, 5+1 = d
or, 6 = d
or, d = 6
therefore, d = 6
The average age of the employees in 2003 is 57.216 years. And, the average age of the employees in 2009 is 59.184 years.
Given that;
The function A(s) given by ,
A (s) = 0.328s + 50
Now for the average age of employees in 2003 and 2009 using the function A(s) = 0.328s + 50, substitute the values of s into the equation.
For the year 2003,
Since s represents the number of years since 1981,
Hence, subtract 1981 from 2003:
s = 2003 - 1981
s = 22
Now substitute this value of s into the function A(s):
A(22) = 0.328 × 22 + 50
A(22) = 7.216 + 50
A(22) = 57.216
Therefore, the average age of the employees in 2003 is 57.216 years.
Similarly, for the year 2009,
s = 2009 - 1981
s = 28
Substituting this value into the function:
A(28) = 0.328 × 28 + 50
A(28) = 9.184 + 50
A(28) = 59.184
Hence, the average age of the employees in 2009 is 59.184 years.
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The mathematical problem involves calculating the average age of employees at a company for the years 2003 and 2009 using the linear function A(s), where 'A(s)' represents the average age and 's' is the number of years since 1981. The calculated average ages for the employees in the years 2003 and 2009 are approximately 57 and 59 years, respectively.
The subject is mathematics, specifically linear functions. Based on the equation A(s) = 0.328s + 50, where 'A(s)' represents the average age of the employees and 's' represents the number of years since 1981. In the year 2003, s would be 22 (2003-1981) and in 2009, s would be 28 (2009-1981).
Substituting these values of 's' into the function gives:
For 2003, A(22) = 0.328*22 + 50 = 57.216
For 2009, A(28) = 0.328*28 + 50 = 59.184
Therefore, the average age of the employees at the company in 2003 and 2009 were approximately 57 and 59 years, respectively.
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