Answers
Given:-
Speed = 36 km/hr
converting speed into m/s
Speed = 36*5/18
Speed = 10 m/s
t = 10 sec
By using the Formula
Distance = Speed * time
D = 10*10
D = 100 m
Hope it helps....
Related Questions
Match each planet to an accurate characteristic
Which of the following organisms has an adaptation that will allow it to survive in tundra biome? *A.)Plants with roots that are short and grows sideways with hairy stems and small leaves.B.)Plants that have broad leaves to capture sunlight and long roots to penetrate the soil.C.)Animals with thin fur that allows them to get rid of heat efficiently.D.)Animals with long tongues for capturing prey and sticky pads for climbing trees.
Dr. John Paul Stapp was a U.S. Air Force officer who studied the effects of extreme acceleration on the human body. On December 10, 1954, Stapp rode a rocket sled, accelerating from rest to a top speed of 282 m/s (1015 km/h) in 5.2 s and was brought jarringly back to rest in only 1 s. Calculate his (a) magnitude of acceleration in his direction of motion and (b) magnitude of acceleration opposite to his direction of motion. Express each in multiples of g (9.80 m/s2) by taking its ratio to the acceleration of gravity. g g
What is 902 in proper scientific notation?
Answers
Answer:
Explanation:
To solve the problem it is necessary to take into account the concepts related to arc length and the radius that make up the measurements of an angle.
An angle is given by the length of arc displaced as a function of the radius, that is
360° is equal to do rad, therefore:
Answers
Answer:
7.84
Explanation:
Draw free body diagram and put all forces on it. Forces are
- Gravity in direction of slope =
=117.6newton
- Viscous force(opposite to slope) after attaining terminal speed =k*V=k*15
As the bike+man system has attained a terminal velocity thus acceleration is zero .
Both forces are opposite then equate them
117.6=k.15
k=7.84
Here k is drag coefficient.
Answer:
0·95
Explanation:
Given the combined mass of the rider and the bike = 100 kg
Percent slope = 12%
∴ Slope = 0·12
Terminal speed = 15 m/s
Frontal area = 0·9 m²
Let the slope angle be β
tanβ = 0·12
As it attains the terminal speed, the forces acting on the combined rider and the bike must be balanced and therefore the rider must be moving download as the directions of one of the component of weight and drag force will be in opposite directions
The other component of weight will get balance by the normal reaction and you can see the figure which is in the file attached
From the diagram m × g × sinβ = drag force
Drag force = 0·5 × d × × v² × A
where d is the density of the fluid through which it flows
is the drag coefficient
v is the speed of the object relative to the fluid
A is the cross sectional area
As tanβ = 0·12
∴ sinβ = 0·119
Let the fluid in this case be air and density of air d = 1·21 kg/m³
m × g × sinβ = 0·5 × d × × v² × A
100 × 9·8 ×0·119 = 0·5 × 1·21 × × 15² × 0·9
∴ ≈ 0·95
∴ Drag coefficient is approximately 0·95
Answers
Answer:
0.5 lambda(wavelength)
Explanation:
We know that
The first harmonic for both side open ended pipe is
L= 1/2lambda
So L = 0.5*wavelength
Answers
Answers
Answer:
0.123 m.
Explanation:
From Hook's law,
The potential energy of the book = the energy stored in the spring.
mgh = 1/2ke².................. Equation 1
Where m= mass of the book, g = acceleration due to gravity, h = height, k = spring constant of the spring, e = distance of compression.
make e the subject of the equation
e = √(2mgh/k).................. Equation 2
Given: m = 1.3 kg, h = 0.8 m, k = 1350 N/m
Constant: g = 9.8 m/s²
Substitute into equation 2
e = √(2×1.3×0.8×9.8/1350)
e = √(20.384/1350)
e = √(0.0151)
e = 0.123 m.
Answer:
0.015m (downwards)
Explanation:
When the book is dropped on the top of the spring at that height, the potential energy () of the book is converted to elastic energy (
) on the spring thereby causing a compression on the spring. i.e
=
But;
The potential energy of the mass (book), is the product of the mass(m) of the book, the height(h) from which it was dropped and the acceleration due to gravity (g). i.e
= - m x g x h [the -ve sign shows a decrease in height as the mass (book) drops]
Also;
The elastic energy () of compression of the spring is given by
=
x k x c
Where;
c = compression length of the spring
k = the spring's constant
Substitute these values of and E into equation (i) as follows;
- m x g x h = x k x c ----------------(ii)
From the question;
m = 1.3kg
h = 0.8m
Take g = 10m/s²
k = 1350N/m
Substitute these values into equation (ii) as follows;
- 1.3 x 10 x 0.8 = x 1350 x c
- 10.4 = 675c
Solve for c;
c = - 0.015 m [The negative sign shows that the spring actually compresses]
Therefore, the maximum distance the spring will be compressed is 0.015m (downwards of course).
planet?
A. You would weigh the same on both planets because the planets
are the same size.
B. You would weigh less on planet A because it has less mass than
planet B.
C. You would weigh the same on both planets because your mass
would be the same on both.
D. You would weigh more on planet A because it has less mass than
planet B.
Answers
The statement which correctly explains the weight you would experience on each planet is: B. You would weigh less on planet A because it has less mass than planet B.
Weight can be defined as the force acting on a body or an object as a result of gravity.
Mathematically, the weight of an object is given by the formula;
Where;
- m is the mass of the object.
- g is the acceleration due to gravity.
Hence, we can deduce that the weight and gravity acting on an object is highly dependent on the mass of an object.
Therefore, the higher the mass in a planet, the higher the gravity existing there.
Read more: brainly.com/question/18320053
Answer:
B
Explanation:
The more mass an object has, the more gravity it has.