(Functions and Relations) Answer getting brainliest!!
(Functions and Relations) Answer getting brainliest!! - 1

Answers

Answer 1
Answer:

Answer:

D

Step-by-step explanation:

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Caitlin earns money as a lifeguard and as a pet sitter. In one week, she earned $25 pet sitting. The total amount of money she earned that week was less than $75. The inequality g + 25 less-than 75 represents g, the possible amount of money she made as a lifeguard.
Select the correct answer. Simplify the following expression. x-2/3 times x 6/7
the cell wall of which out of this is not made up of cellulose bacteria mango tree hydrilla cactus which one is correct​
Don’t understand please help

Layla is cutting bows out of ribbon which will be used to wrap gifts. If Layla needs 21/22of a foot of ribbon to make a bow, and she has 21 feet of ribbon, then how many bows can Layla make?​

Answers

Answer:

21 bows

Step-by-step explanation:

Since 21/22 is just 1 short of a whole 1, we can first round it up to a whole 1, and subtract it later. 21 divided by 1 is just 21, and now is the time to subtract the part in which we rounded out. 1/22 times 21 is 21/22, so Layla can't make an entire bow with it.

2Select the correct answer.
Which value is needed to determine a confidence interval for a sample mean?
OA
the margin of error for the proportion
ов.
the population size
OC.
the sample proportion
OD
the standard error of the mean

Answers

The value needed to determine a confidence interval for a sample mean is the standard error of the mean option (D) is correct.

What is a confidence interval for population standard deviation?

It is defined as the sampling distribution following an approximately normal distribution for known standard deviation.

The formula for finding the confidence interval for population standard deviation as follows:

\rm s\sqrt{(n-1)/(\chi^2_(\alpha/2, \ n-1))} < \sigma < s\sqrt{(n-1)/(\chi^2_(1-\alpha/2, \ n-1))}

Where s is the standard deviation.

n is the sample size.

\chi^2_(\alpha/2, \ n-1) and \chi^2_(1-\alpha/2, \ n-1) are the constant based on the Chi-Square distribution table:

α is the significance level.

σ is the confidence interval for population standard deviation.

Calculating the confidence interval for population standard deviation:

We know significance level = 1 - confidence level

 

It is given that:

The value needed to determine a confidence interval for a sample mean is the standard error of the mean.

CI = X + Z(s/√n)

Here CI is the confidence interval

Z is the confidence level

X is the sample mean

Thus, the value needed to determine a confidence interval for a sample mean is the standard error of the mean option (D) is correct.

Learn more about the confidence interval here:

brainly.com/question/6654139

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Answer:

D.thestandarderrorofthemean

Step-by-step explanation:

trust me i got it right Plato

Select the three ratios that represent the number of red cars to blue cars

Answers

We need to see the picture of the problem

Toy company produces rubber balls that have a radius of 1.7 cm.A sphere has a radius of 1.7 centimeters.
What is the volume of one rubber ball? Round to the nearest hundredth of a centimeter.

Answers

Answer:

The volume of one rubber ball is 20.58 cubic centimeters.

Step-by-step explanation:

The rubber ball has a spheric format.

A sphere with radius r has volume given by the following equation:

V = (4\pi r^(3))/(3)

In this question:

r = 1.7 cm.

The radius is in centimeters, so the volume will be in cubic centimeters.

What is the volume of one rubber ball?

V = (4*\pi*(1.7)^(3))/(3) = 20.58

The volume of one rubber ball is 20.58 cubic centimeters.

Answer:

1) 20.58 cm

2) $0.09

3) $0.41

Step-by-step explanation:

The taxes on a house assessed at $78,000 are $1950 a year. If the assessment is raised to $93,000 and the tax rate did not change, how much would the taxesbe now?

Answers

Answer:

i dont do taxes

Step-by-step explanation:

Law School According to the Law School Admission Council, in the fall of 2007, 66% of law school applicants wereaccepted to some law schooL4 The training program LSATisfaction claims that 163 of the 240 students trained in 2006were admitted to law school. You can safely consider these trainees to be representative of the population of law schoolapplicants. Has LSAfisfaction demonstrated a real improvement over the national average?a) What are the hypotheses?b) Check the conditions and find the P-value.c) Would you recommend this program based on what you see here? Explain.

Answers

Answer:

a) H_(0): p = 0.66\nH_A: p > 0.66

b) P-value = 0.2650

c) No, this programme will not be recommended as there is no real improvement over the national average.

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 240

p = 66% = 0.66

Alpha, α = 0.05

Number of students admitted to law school , x = 163

a) First, we design the null and the alternate hypothesis  

H_(0): p = 0.66\nH_A: p > 0.66

This is a one-tailed(right) test.  

Formula:

\hat{p} = (x)/(n) = (163)/(240) = 0.6792

z = \frac{\hat{p}-p}{\sqrt{(p(1-p))/(n)}}

Putting the values, we get,

z = \displaystyle\frac{0.6792-0.66}{\sqrt{(0.66(1-0.66))/(240)}} = 0.6279

b) Now, we calculate the p-value from the table.

P-value = 0.2650

c) Since the p-value is greater than the significance level, we fail to reject the null hypothesis and accept the null hypothesis.

Thus, there is no real improvement over the national average.

No, this programme will not be recommended as there is no real improvement over the national average.