A bookstore charges a standard rate for paperback or hardback books. The cost of a paperback book is 11 dollars less than the cost of a hardback book. Recently one day of sales totaled $784.10. That day the bookstore sold 53 paperback books and 45 hardback book. Write a system representing the situation. Use the graph test made the solution of the system. What does the solution mean to the situation? How much does each type of book cost? You substitution to verify your solution.

Answers

Answer 1

Answer:

The required price of the paperback book and hardback book is $2.95 and $13.95 respectively.

Given that,
The cost of a paperback book is 11 dollars less than the cost of a hardback book. Recently one day of sales totaled $784.10. That day the bookstore sold 53 paperback books and 45 hardback book.

What are simultaneous linear equations?

Simultaneous linear equations are two- or three-variable linear equations that can be solved together to arrive at a common solution.

Here,
Let the price of paperback be x and price of hardback books be y,
According to the question,
x = y - 11 - - - (1)
53x + 45y = 784.10 - - - (2)
From equation 1
53 [y - 11] + 45y = 784.10
y = $13.95

Now,
y = 13.95 - 11
y = $2.95

Thus, the required price of the paperback book and hardback book is $2.95 and $13.95 respectively.

Learn more about simultaneous equations here:

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Answer 2

Answer: p = h - 11
53p + 45h = 784.10

just a matter of subbing and solving...
53(h - 11) + 45h = 784.10
53h - 583 + 45h = 784.10
98h = 784.10 + 583
98h = 1367.10
h = 1367.10/98
h = 13.95

p = h - 11
p = 13.95 - 11
p = 2.95

so paperbacks (p) are 2.95 a piece and hardbacks (h) are 13.95 a piece

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