An isosceles trapezoid has legs that measure 10 cm and bases of 12 cm and 2 cm. The base angles measure 60°. Find the height and the area of the trapezoid.

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Answer 1
Answer: I hope this helps you

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2x + 2y = 288x - 2y= 22 system of equations
How do i solve this inequality?

Write the fraction as a percent. Round to the nearest tenth of a percent if necessary. 49/100

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49 ÷ 100

= 0.49

0.49 x 100 = 49%

Jamie has 3 times as many pencils as pens. She has at least 18 pencils. How many pens does Jamie have?

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jamie has 54 pens in total and in simplefied ratio is 27:9
jamie has 3 times as many pencils as pen and jamie has 18 pencils so you multiply 3x18=54

Order the fractions -1/2, 5/2, -12/4, 1/6, and 7/8 from least to greatest

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-12/4 then -1/2 then 1/6 then 7/8 then 5/2
Hope I helped :)

(3*1,000)+(3*10)+*(3*1/100)+(3*1/1000)

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3030.033
Just put each 3 in the correct place value

Sin A - 2 sin cube A
---------------------------
2 cos cube A - cos A

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(sin\alpha-2sin^3\alpha)/(2cos^3\alpha-cos\alpha)=(sin\alpha(1-2sin^2\alpha))/(cos\alpha(2cos^2\alpha-1))=(sin\alpha(1-sin^2\alpha-sin^2\alpha))/(cos\alpha(cos^2\alpha+cos^2\alpha-1))\n\n=(sin\alpha(cos^2\alpha-sin^2\alpha))/(cos\alpha(cos^2\alpha-sin^2\alpha))=(sin\alpha)/(cos\alpha)=tan\alpha\n\n\nsin^2\alpha+cos^2\alpha=1\to cos^2\alpha=1-sin^2\alpha\nsin^2\alpha+cos^2\alpha=1\to sin^2\alpha=1-cos^2\alpha\to-sin^2\alpha=cos^2\alpha-1

Which statement about the ordered pairs (-9, 3) and (2, - 4) is true for the equation6x - y/2 = 14?

(-9, 3) is a solution to the equation.
(2, - 4) is a solution to the equation.
Neither ordered pair is a solution.
Both ordered pairs are solutions.

Answers

Answer:

(2, - 4) is a solution to the equation

Step-by-step explanation:

Substitute the x and y coordinates of the points into the left side of the equation and if equal to the right side then they are a solution.

(- 9, 3 )

6(- 9) - (3)/(2)

= - 54 - 1.5 = - 55.5 ≠ 14 ← not a solution

(2, - 4)

6(2) - (-4)/(2)

= 12 + 2 = 14 ← This is a solution

Thus (2, - 4) is a solution to the equation