Answer:
6 ¼ hours of Daylight
Step-by-step explanation:
one half cubed − 2 ÷ square root of 64
negative fifteen sixty fourths
fifteen sixty fourths
negative one eighth
one eighth
The solution to one half cubed − 2 ÷ square root of 64 is negative one eighth
The expression is given as:
one half cubed − 2 ÷ square root of 64
Rewrite the expression properly as follows:
(1/2)^3 − 2/√64
Take the square root of 64
(1/2)^3 − 2/8
Evaluate the quotient of 2 and 8
(1/2)^3 − 1/4
Take the cube of 1/2
1/8 - 1/4
Evaluate the difference
-1/8
Hence, the solution to one half cubed − 2 ÷ square root of 64 is negative one eighth
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the answer is 1/13 ². Because if you divide 1/169 and 1/13, then you get 1/13. With that being said, if you multiply 1/13 and 1/13, then you get 1/169. And of course the symbol ( ² ) means squared so you multiply that number he (² ) is over twice. So like 3², 3*3=9.
Helpful???
y = –3x + 11
A.
(6, -3)
B.
(6, -7)
D.
(5, -4)
C:
Hi Brainiac
3x+2y=7
y=-3x+11
We need to solve y=-3x+11 for y
Now let's start by substitute -3x+11 for y in 3x+2y=7
3x+2y=7
3x+2(-3x+11)=7
-3x+22=7
Now add -22 to both sides
-3x+22-22=7-22
-3x=-15
To find the value for x we need to divide both sides by -3
-3x/-3= -15/-3
x=5
Now we have the value for x :)
Let's find the value for y by substitute 5 for x in y=-3x+11
y=-3x+11
y=-3(5)+11
y=-4
Here you go :)
The answer is D
Good luck :0
Options:
NONE
ASA
SSS
SAS
AAS
HL
Step-by-step explanation:
(csc θ − 1) / cot θ
Multiply top and bottom by the conjugate csc θ + 1.
(csc θ − 1) (csc θ + 1) / (cot θ (csc θ + 1))
Distribute.
(csc²θ − 1) / (cot θ (csc θ + 1))
Use Pythagorean identity.
cot²θ / (cot θ (csc θ + 1))
Divide.
cot θ / (csc θ + 1)