-5x is the argument in the first log
6x+12 is the argument in second log
FIND THE DOMAIN AND THE SOLUTION TO X
Ps: just starting on algebra, so might not be right.
Find the domain by finding where the equation is defined.
Interval Notation:
(−2,0)∪(5,∞)
Set-Builder Notation:
{x|−2<x<0,x>5}
Solve for x
For two functions to be equal, the arguments of each must be equal.
x=12,−1
I hope this isn't wrong and if it is, sorry...