What are the domain, range, and asymptote of h(x) = (0.5)x – 9?domain: {x | x > 9}; range: {y | y is a real number}; asymptote: y = 9  

domain: {x | x > –9}; range: {y | y is a real number}; asymptote: y = –9  

domain: {x | x is a real number}; range: {y | y > 9}; asymptote: y = 9 

domain: {x | x is a real number}; range: {y | y > –9}; asymptote: y = –9

Answers

Answer 1
Answer:

Answer:

Option 4 - domain: {x | x is a real number}; range: {y | y > –9}; asymptote: y = –9

Step-by-step explanation:

Given :  h(x)=(0.5)^x-9

To find : What are the domain, range, and asymptote of h(x) ?

Solution :  

Domain of the function is where the function is defined

The given function  h(x)=(0.5)^x-9 is an exponential function

So, the domain of the function is,

D=(-\infty,\infty) , x|x\in \mathbb{R}

i.e, The set of all real numbers.

Range is the set of value that corresponds to the domain.

Let  y=(0.5)^x-9

If x\rightarrow \infty , y\rightarrow -9

If x\rightarrow -\infty , y\rightarrow \infty

So, The range of the function is

R=(-9,\infty) , y|y>-9

The asymptote of the function,

Exponential functions have a horizontal asymptote.

The equation of the horizontal asymptote is  when

x\rightarrow \infty

y=(0.5)^\infty-9

y=-9

Therefore, Option 4 is correct.

Domain: {x | x is a real number}; range: {y | y > –9}; asymptote: y = –9

Answer 2
Answer: Among the choices provided above the  domain, range, and asymptote of h(x) = (0.5)x – 9 is the below:

domain: {x | x is a real number}; range: {y | y > –9}; asymptote: y = –9 

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Which ratio forms a proportion with 16/20

Answers

Answer:

4/5 forms a proportion with 16/20.

Step-by-step explanation:

We are given an rational number as 16/20.

we have to find another rational number which is equivalent to it.

as both 16 and 20 are multiple of 4 we could also represent the ratio 16/20 as:

(16)/(20)=(4 * 4)/(4*5)

we cancel 4 on both the numerator and denominator to get (4)/(5).

Hence,  the ratio (4)/(5) is proportion with (16)/(20).


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and explenation :)

Answers

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What is the chance of rolling a 4 with a single dice 3 times

Answers


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If you already have two, then the chance of rolling another one is  1/6 .

So, starting from the beginning, the chance of rolling three of them
IN THREE TOSSES is

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0.7(3s+4)−1.1s=7.9 I need a answer

Answers

First, expand the bracket

2.1s + 2.8 - 1.1s = 7.9

Next, collect like terms

s + 2.8 = 7.9

Lastly subtract 2.8 from 7.9 to get your answer.

s = 5.1

(Hope this helps! ^^)

Answer:

\boxed {s = 5.1}

Step-by-step explanation:

Solve for the value of s:

0.7(3s + 4) - 1.1s = 7.9

-Use Distributive Property:

0.7(3s + 4) - 1.1s = 7.9

2.1s + 2.8 - 1.1s = 7.9

-Combine like terms:

2.1s + 2.8 - 1.1s = 7.9

s + 2.8  = 7.9

-Subtract 2.8 to both sides:

s + 2.8 - 2.8 = 7.9 - 2.8

\boxed {s = 5.1}

So, the value of x is 5.1.

Can anyone help me with this:

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Answers

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Answers

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Median: the middle number in a set of data
Mode: the most common number that appears in a set of data
Range: biggest number take away the smallest number
Mode: number that appears the most
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Range: subtract the highest number from the smallest number
Median: put the numbers from least value to the top value and the Median will be in the middle