olivia has 18 marbles ,mason has 24 marbles,nia has 63 marbles,and eric has 75 marbles. each person packaged their marbles in groups of 9 after the marbles are packaged,who will have marbles left over

Answers

Answer 1
Answer:

Answer:

Mason's and Eric's

Step-by-step explanation:

We are given that:

Olivia has 18 marbles ,Mason has 24 marbles,Nia has 63 marbles,and Eric has 75 marbles.

Each person packed their marbles in groups of 9.

We have to find who will have marbles left over.

Olivia has 18 marbles which can be packed as (9+9=18)

Mason has 24 marbles which can be packed as (9+9=18 and 6 will be left unpacked)

Nia has 63 marbles which can be packed as (9+9+9+9+9+9+9=63)

and Eric has 75 marbles which can be packed as (9+9+9+9+9+9+9+9=72 and 3 will be left unpacked)

Hence, Mason's and Eric's marbles are left unpacked

Answer 2
Answer: Mason will have 6 left over Eric will have 3 left over.

Oliva= 9 +9 = 18 ( no left over)
Mason= 9+9=18+6 =24 ( 6 left over)
Nia= 9+9+9+9+9+9+9=63 (no left over)
Eric= 9+9+9+9+9+9+9+9=72+3=75 (3 left over)

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Drag and drop a statement or reason to each box to complete the proof.Given: parallelogram EFGH

Prove: EG bisects HF and HF bisects EG.

Answers

Answer:

Given : EFGH is a Parallelogram

Prove : EG Bisects HF , HF Bisects EG

Step-by-step explanation:

Proof

Check image below

Answer:

Given Parallelogram EFGH

EG bisects HF and HF bisects EG, if and only if both the diagnols have same mid point.

Step-by-step explanation:

Step 01:

Let

E be the point (a,b)

F be the point (a',b)

G be the point (a',b')

H be the point (a,b')

Step 02:

Now find mid points of EG and HF

mid point of EG = ( (a+a')/(2), (b+b')/(2) ) and

mid point of HF = (  (a'+a)/(2),(b'+b)/(2) )

Since addition is commutative, and they have the same mid-point, so they bisect each other.

Triangle ABC has a perimeter of 22cmAB=8cm
BC=5cm
By calculations, deduce whether triangle ABC is a right angled triangle

Answers

ΔABC is not a right angled triangle.

Step-by-step explanation:

  • Step 1: Given perimeter of ΔABC = 22 cm, AB = 8 cm and BC = 5 cm. Find AC.

Perimeter = AB + BC + AC

⇒ AC = 22 - (8 + 5) = 22 - 13 = 9 cm

  • Step 2: Find whether the triangle is right angled using Pythagoras Theorem.

AC² = AB² + BC²

⇒ AC² = 9² = 81

⇒ AB² + BC² = 8² + 5² = 64 + 25 = 89

∴ AC² ≠ AB² + BC²

ΔABC is not a right angled triangle.

75% of x peaches is 15 peaches

Answers

If you would like to solve 75% of x peaches is 15 peaches, you can calculate this using the following steps:

75% of x peaches is 15 peaches
75% * x = 15
75/100 * x = 15     /*100/75
x = 15 * 100 / 75
x = 20 peaches

Result: 75% of 20 peaches is 15 peaches.
75% of 20 peaches is 15 peaches!

Find the vertex of this parabola:
y = -5x2 - 10x - 15
Enter the correct answer.

Answers

Answer:

Vertex of parabola (-1, -10)

Step-by-step explanation:

For a given quadratic y = ax² + bx + c, the vertex (h, k) is found by computing h = –b/2a, and then evaluating y at h to find k. If you've already learned the Quadratic Formula, you may find it easy to memorize the formula for k, since it is related to both the formula for h and the discriminant in the Quadratic Formula: k = (4ac – b2) / 4a.

Absolute Value
8+|3y - 5|=15

Answers

minus 8 oth sides
|3y-5|=7

assume that if you have
|x|=y
assume
x=y and x=-y are 2 solutions

3x-5=7 and
3x-5=-7
solve

3x-5=7
3x=12
x=4

3x-5=-7
3x=-2
x=-2/3

x=4 or -2/3

How to work out:
5x+1=2x-8

Answers

5x+1=2x-8 \n 5x-2x=-8+1 \n 3x=-7 \n x=-7/3

S= {-7/3}
5x+1=2x-8
3x=-7
x=-7/3