The correct simplest formof 29 percent as a fraction is 29/100, where numerator is 29 and denominator is 100.
A fractions is a part of whole or a numerical number that isn't a whole number the upper value of line is called numerator and the number below the line is called denominator.
Percentages are as a fractions where the denominator is 100.
29% = 29 ÷ 100 = 29/100 or 0.29
29/100 here 29 is a numerator and 100 is denomenator.
Therefore, the simplest form for 29 percent is 29/100.
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Answer:
29/100
Step-by-step explanation:
29 = 29/100
Arithmetic Sequence
The value of the 93th term of this arithmetic series is -925
Step-by-step explanation:
The first term of the arithmetic term is a = -5
And the common difference is d = a2-a1 = -15 - ( - 5) = -10
So the 93th term if this arithmetic progression is given by
an = a + (n-1) × d
where an is the nth term of the arithmetic progression
so in order to calculate the 93rd term (a93), the value of n = 93
so a93 = -5 + (93-1) × (-10)
a93 = -5 + (-920)
a93 = -925
Hence the value of the 93th term of this arithmetic series is -925
The 93rd term of the arithmetic sequence is -925.
Here, we have to find the nth term of an arithmetic sequence, you can use the formula:
nth term = first term + (n - 1) * common difference
where:
first term = the first term of the sequence
common difference = the difference between consecutive terms
n = the term number you want to find
In this case, we have the arithmetic sequence:
-5, -15, -25, ...
Here, the first term (a) is -5,
and the common difference (d) is -15 - (-5) = -10.
Now, we want to find the 93rd term (n = 93) of this sequence.
nth term = -5 + (93 - 1) * (-10)
nth term = -5 + 92 * (-10)
nth term = -5 + (-920)
nth term = -925
So, the 93rd term of the arithmetic sequence is -925.
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The difference between what they paid for each uniform and what they got for each return is $1400.
An expression is a number, or a variable, or a combination of numbers and variables and operation symbols.
Now it is given that,
Number of uniforms bought = 40
Total cost of uniforms = $3000
Now given returning cost = $40 per uniform
So, returning cost of all uniforms = $40*40
⇒ returning cost of all uniforms = $1600
Thus, the difference between what they paid for each uniform and what they got for each return = $3000- $1600
⇒ the difference between what they paid for each uniform and what they got for each return = $1400
Thus, the difference between what they paid for each uniform and what they got for each return is $1400.
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