I need the pattern for these numbers,1, 8, 27, 64, _, _, _, _, _

and

2, 3, 5, 7, 11, 13, _, _, _, _, _

Answers

Answer 1

Answer: 1) 1,8,27,64,95,126,176,230

2)14,16,18,22,24

Hope this helps :)

Answer 2

Answer: The second pattern is in prime numbers. Each number is a prime number in a successive order.2,3,5,7,11,13, [17,19,23,29,31], 37, 41, etc..

Related Questions

Ann has to make payments twice a year on her health insurance. if each payment is $2,316, how much money should she budget for health insurance each month?A. $579B. $386C. $1,158D. $193
Solve: 4y - 6 = 2y + 8
Fabio and Carlos play on a basketball team together. In the last game, Fabio had 7 points less than 2 times as many points as Carlos. Fabio scored 31 points in the game.
3. 2x – y = -74x – y = -4 A) (-1.5, 4) B) (1.5, 10) C) (4, -1.5) D) (-1.5, -2)
Find a set of consecutive counting numbers whose sum is 154. Each set may consist of 2 comma 3 comma 4 comma 5 comma or 6 consecutive integers. Use the spreadsheet activity Consecutive Integer Sum on our Web site to assist you.Give the smallest number of the set for each set. If there are no such numbers, put "x" as your answer.

A clown weighs 60 lb more than a trapeze artist. The trapeze artist weighs two thirds as much as the clown. How much does each weigh? Choices for the weight of the trapeze artist: 110, 120, 125

Answers

The weight of the trapeze artist is 110

Simplify. Write in radical form.
(x^3y^-2/xy)^-1/5

Answers

Answer:

The radical form of the expression $((x^3y^(-2))/(xy))^{(-1)/(5)}$ is $\sqrt[5]{(y^3)/(x^2)}$

Step-by-step explanation:

Given : $((x^3y^(-2))/(xy))^{(-1)/(5)}$

We have to simplify the given expression and write in radical form.

RADICAL FORM is the simplest form of expression that do not involve any negative exponent and power is less than n, where n is the nth root of that expression.

Consider the given expression $((x^3y^(-2))/(xy))^{(-1)/(5)}$

Cancel out the common factor x, we get,

$((x^2y^(-2))/(y))^{(-1)/(5)}$

Using laws of exponents, $a^(-m)=(1)/(a^m)$ , we have,

$((x^2)/(y\cdot y^2))^{(-1)/(5)}$

Using laws of exponents, $x^m \cdot x^n=x^(m+n)$ , we have,

$((x^2)/(y^3))^{(-1)/(5)}$

Again using laws of exponents, $a^(-m)=(1)/(a^m)$ , we have,

$((y^3)/(x^2))^{(1)/(5)}$

Also, written as $\sqrt[5]{(y^3)/(x^2)}$

Thus, the radical form of the expression $((x^3y^(-2))/(xy))^{(-1)/(5)}$ is $\sqrt[5]{(y^3)/(x^2)}$

Hope this helped! Much luck!

Triangle ABC underwent a sequence of transformations to give triangle A′B′C′. Which transformations could not have taken place? A. a reflection across the line y = x followed by a reflection across the line y = -x B. a reflection across the x-axis followed by a reflection across the y-axis C. a rotation 180° clockwise about the origin followed by a reflection across the line y = x D. a reflection across the y-axis followed by a reflection across the x-axis

Answers

Answer:

C. a rotation 180° clockwise about the origin followed by a reflection across the line y = x

Step-by-step explanation:

Let us assume that the coordinate of A in triangle ABC is A(x, y)

A) If there is a reflection across line y = x, the new coordinate is at A'(y, x).

If a reflection across the line y = -x is then followed, the new coordinate is at A"(-x, -y)

B) If there is a reflection across line x axis, the new coordinate is at A'(x, -y).

If a reflection across the line y axis is then done, the new coordinate is at

A"(-x, -y)

C) If there is a rotation 180° clockwise about the origin, the new coordinate is at A'(-x, -y).

If a reflection across the line y = x is then followed, the new coordinate is at A"(-y, -x)

D) B) If there is a reflection across line y axis, the new coordinate is at A'(-x, y).

If a reflection across the line x axis is then done, the new coordinate is at

A"(-x, -y)

Since only option C has a different result from the remaining options, hence option C would not five triangle A'B'C'

Answer:

C. a rotation 180° clockwise about the origin followed by a reflection across the line y = x

Step-by-step explanation:

Let us assume that the coordinate of A in triangle ABC is A(x, y)

A) If there is a reflection across line y = x, the new coordinate is at A'(y, x).

If a reflection across the line y = -x is then followed, the new coordinate is at A"(-x, -y)

B) If there is a reflection across line x axis, the new coordinate is at A'(x, -y).

If a reflection across the line y axis is then done, the new coordinate is at

A"(-x, -y)

C) If there is a rotation 180° clockwise about the origin, the new coordinate is at A'(-x, -y).

If a reflection across the line y = x is then followed, the new coordinate is at A"(-y, -x)

D) B) If there is a reflection across line y axis, the new coordinate is at A'(-x, y).

If a reflection across the line x axis is then done, the new coordinate is at

A"(-x, -y)

Since only option C has a different result from the remaining options, hence option C would not five triangle A'B'C'

Multiply or Divide

(i need this for school tomorrow)

Answers

Answer:

Ok so here are the simple rules of doing it (very easy) cause I’m not doing it all so . when multiplying a power with The same base keep the base but add the exponents. Dividing, keep the base (if their the same if not then its already simplified same with multiplication) but SUBTRACT the exponents. Also keep the parenthesis if it’s a negative number base.

I’ll do a few.

11) a^10. 11b) 5^4

12) (-2)^2.

13) 10^2. 13b) s^6

14) -4s^5(t^6) <- [Im not sure of this one)

15) x^3(y^3)

Suppose that y varies inversely with x. Write an equation for the inverse variation. Y =4 when x =7

Answers

If y varies inversely as x, then we write it as:
y = k/x

where k is some constant.

If we multiply both sides of this equation by x we get an equation for k:
k = x*y

We are given that y=4 when x=7, therefore:
k = 7*4 = 28

Put this back into our original equation to get:
y = 28/x

My question is, what is: log6(4x-8)=3