Identify the terminal point for a 60° angle in a unit circle.A.
22
B. (1,1)
c. (7)
D. (5.)

Answers

Answer 1

Answer:

Identify the terminal point for a 60° angle in a unit circle.

What is the terminal angle?

Terminal point definition the final destination or station of a bus or rail journey | Meaning, pronunciation, translations, and examples.

for the terminal point for a 60-degree angle in a unit circle.

Therefore the correct option is D.

Therefore, the 1/3 and root(3)/2.

To learn more about terminal angle visit:

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Answer 2

Answer:

Answer:

it's A

Step-by-step explanation:

i hope this helps :D

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Please help.2/3x - 4 = -2A) -3B) -4C) -9D) 3

Which of the four Venn diagrams represents this?

Answers

Answer:

I would day option B does

Answer:

A is the correct answer

Step-by-step explanation:

Solve this answer PLEASE ASAP!!
MATH i will reward brainliest! :)

Answers

The answer you’re looking for is -1/2. Good luck! :)

(2/3)/(-4/3) = -0.5 and/or -1/2

You drop a rock off a bridge. The rock’s height, h (in feet above the water), after t seconds is modeled by h = -16t^2 + 541. What is the height of the rock after 2 seconds?

Answers

For this case we have the following equation:
$h = -16t ^ 2 + 541$
To answer the question, what we must do is evaluate the function for t = 2.
We have then:
$h = -16 (2) ^ 2 + 541$
Rewriting we have:
$h = -16 (4) + 541h = -64 + 541h = 477 feet$
Answer:
The height of the rock after 2 seconds is:
$h = 477 feet$

Determine the maximized area of a rectangle that has a perimeter equal to 56m by creating and solving a quadratic equation. What is the length and width?

Answers

Answer:

Area of rectangle = $196\,m^2$

Length of rectangle = 14 m

Width of rectangle = 14 m

Step-by-step explanation:

Given:

Perimeter of rectangle is 56 m

To find: the maximized area of a rectangle and the length and width

Solution:

A function $y=f(x)$ has a point of maxima at $x=x_0$ if $f''(x_0)<0$

Let x, y denotes length and width of the rectangle.

Perimeter of rectangle = 2( length + width )

$=2(x+y)$

Also, perimeter of rectangle is equal to 56 m.

So,

$56=2(x+y)\nx+y=28\ny=28-x$

Let A denotes area of rectangle.

A = length × width

$A=xy\n=x(28-x)\n=28x-x^2$

Differentiate with respect to x

$(dA)/(dx)=28-2x$

Put $(dA)/(dx)=0$

$28-2x=0\n2x=28\nx=14$

Also,

$(d^2A)/(dx^2)=-2<0$

At x = 14, $(d^2A)/(dx^2)=-2<0$

So, x = 14 is a point of maxima

So,

$y=28-x=28-14=14$

Area of rectangle:

$A=xy=14(14)=196\,m^2$

Length of rectangle = 14 m

Width of rectangle = 14 m

There are 12 coins ; dimes and quarters. The number of dimes is 2 more than the number of quarters. A. $2.25
B. $2.10
C. $2.50
D. $1.95
E. $1.65
F. $1.80
You have 15 coins; dimes and quarters. The number of quarters is twice as many as dimes. Find the total value of the coins.
A. $2
B. $3.25
C. $3.50
D. $2.50
E. $2.25
F. $3

Answers

Answer:

D. $1.95

F. $3

Step-by-step explanation:

dimes: x + 2

quarters: x

x + 2 + x = 12

2x + 2 = 12

2x = 10

x = 5

dimes: x + 2 = 5 + 2 = 7

quarters: x = 5

Total value: (7 * .10) + (5 * .25) = $1.95

_____

dimes: x

quarters: 2x

x + 2x = 15

3x = 15

x = 5

dimes: x = 5

quarters: 2x = 2(5) = 10

Total value: (5 * .10) + (10 * .25) = $3

The graph shows the distance, y, that a car traveled in x hours: A graph is shown with the x-axis title as Time in hours. The title on the y-axis is Distance Traveled in miles. The values on the x-axis are from 0 to 5 in increments of 1 for each grid line. The values on the y-axis are from 0 to 325 in increments of 65 for each grid line. A line is shown connecting ordered pairs 1, 65 and 2, 130 and 3, 195 and 4, 260. The title of the graph is Rate of Travel. What is the rate of change for the relationship represented in the graph? (1 point) fraction 1 over 65 fraction 1 over 64 64 65