Answer:
#4
2.50 out of 15 is:
#5
Percent increase:
Answer:
8 cubes are painted on 3 sides
24 cubes are painted on 2 sides
22 cubes are painted on 1 sides
6 cubes are painted on 0 side
E = 3 * 8/60 + 2 * 24/60 + 1 * 22/60 + 0 * 6/60 = 47/30 = 1.567
In the problem, if we denote the number of lions as x, the number of tigers as x+2, and the number of bears as x+3, and considering that the total of all these animals is exactly 20, we can form and solve a simple algebraic equation. We will find that there are 5 lions, 7 tigers, and 8 bears.
This is a problem of simple algebra. According to the problem, let's represent the number of lions as x, the total number of tigers as x + 2 (since it's two more than the lions), and the number of bears as x + 3 (1 more than the number of tigers).
The problem states the total number of all these animals as 20, so we can set up the following equation: x + x + 2 + x + 3 = 20.
Solving this algebra equation gives you:
3x + 5 = 20
Subtracting 5 from both sides gives us:
3x = 15
Dividing both sides by 3 gives us:
x = 5
So, the number of lions is 5, the number of tigers is 7 (5 + 2), and the number of bears is 8 (7 + 1).
#SPJ2
Answer:
40%
Step-by-step explanation:
a.p.e.x
Answer:
Draw 20 equilateral triangles such that 5 triangles having sides measure 4 cm , 7 triangles have sides measure 7 cm , 3 triangles have side 10 cm and rest of the triangles have side of measure 5 cm.
This will become a set of equilateral triangles .
Let consider a subgroup set of the original set of having equilateral triangle with side-length of 5 cm.
Then the number of triangle having side-length 5 cm= 20-5-7-3=5
Now, the fraction of the group having triangle with side- length 5 cm is given by:-
B.2x + 4y
C.2x - 12y
D.6x - 12y
Answer:
theres no picture attached
Step-by-step explanation: