Answer:
13 3/4
Step-by-step explanation:
train B leaves Bridgton and heads east at
100 mi/h. At what time will train B catch
up to train A?
Train B will catchup to Train A at 5:30 PM.
We have,
d = distance covered by both trains when they meet
t = time it takes for train B to catch up to train A
For train A:
Distance = Speed × Time
d = 90t
For train B:
Distance = Speed × Time
d = 100(t - 0.5) (train B departs 30 minutes (0.5 hours) later than train A)
Since both equations represent the samedistance, we can set them equal to each other:
90t = 100(t - 0.5)
Let's solve for t:
90t = 100t - 50
10t = 50
t = 5
It will take 5 hours for train B to catchup to train A.
To determine the time when train B catches up to train A, we add the 5 hours to the departure time of train B, which is 12:30 PM:
12:30 PM + 5 hours = 5:30 PM
Therefore,
Train B will catchup to Train A at 5:30 PM.
Learn more about speed here:
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I'd say maybe by 5:30 b would
A.
21 square meters
B.
42 square meters
C.
54 square meters
D.
108 square meters
The total number of handshakes that would happen between the three people are:
3
There are three people at a party.
Let they be denoted by A,B and C.
Now, the total number of handshakes that would occur will be denoted by:
AB, AC and BC
where AB denotes that A and B shake hands.
AC denote that A and C shake hands.
and BC denote that B and C shake hands.
Hence, total number of handshakes are:
3