MATHEMATICS COLLEGE

PLEASE ANSWER ILL GIVE YOU BRAINLIEST

Answers

Answer 1

Answer:

Answer:

V=3052.1 square units.

Step-by-step explanation:

Using the formulas

V=4

3πr^3

d=2r

Solving for V

V=1

1/6πd^3=1

1/6·3.14·18^3=3052.08

round to the nearest tenth place so your volume would be 3052.1 :)

Answer 2

Answer:

Answer:

3052.1

Step-by-step explanation:

The formula for volume of a sphere: 4/3 x pi x r^3 (4/3 x pi x radius x radius x radius).

Here, only the diameter is shown. To find the radius, we must divide the diameter (18) by 2.

18 / 2 = 9

9 is the radius.

Now, we have our final equation:

4/3 x pi x radius x radius x radius

4/3 x 3.14 x 9 x 9 x 9 = 3052.08

(3.14 is commonly used for pi)

3052.08 rounded to the nearest tenth is 3052.1

Therefore, 3052.1 is the volume of the sphere.

Related Questions

What is the GCF & LCM of 8 and 44
Which statement illustrates why cosine is an even function?cos(pie/4) = -cos(5pie/4)cos(pie/4) = -cos(4pie/4) cos(-pie/4) = cos(pie/4)cos(-7pie/6) = cos(5pie/4)
Given the following function , find f(-2) ,f (0) and f(2) F(X)=-3x-3 F(-2) = help me please i don't understand
What is the value of the angle on the top left of this quadrilateral 112°88°90°70°
Drag numbers to use a negative factor to factor the expression-5g+15h-25

In determining automobile-mileage ratings, it was found that the mpg (X) for a certain model is normally distributed, with a mean of 33 mpg and a standard deviation of 1.7 mpg. Find the following:__________. a. P(X<30)
b. P(28c. P(X>35)
d. P(X>31)
e. the mileage rating that the upper 5% of cars achieve.

Answers

The upper 5% of cars have a mileage rating of 35.805 mpg

What is z score?

Z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:

z = (raw score - mean) / standard deviation

Given; mean of 33 mpg and a standard deviation of 1.7

a) For < 30:

z = (30 - 33)/1.7 = -1.76

P(x < 30) = P(z < -1.76) = 1 - 0.8413 = 0.0392

b) For < 28:

z = (28 - 33)/1.7 = -2.94

P(x < 28) = P(z < -2.94) = 0.0016

c) For > 35:

z = (35 - 33)/1.7 = 1.18

P(x > 35) = P(z > 1.18) = 1 - P(z < 1.18) = 1 - 0.8810 = 0.119

d) For > 31:

z = (31 - 33)/1.7 = -1.18

P(x > 31) = P(z > -1.18) = 1 - P(z < -1.18) = 0.8810

e) The upper 5% of cars achieve have a z score of 1.65, hence:

1.65 = (x - 33)/1.7

x = 35.805 mpg

The upper 5% of cars have a mileage rating of 35.805 mpg

Find out more on z score at: brainly.com/question/25638875

Answer:

a) P(X < 30) = 0.0392.

b) P(28 < X < 32) = 0.2760

c) P(X > 35) = 0.1190

d) P(X > 31) = 0.8810

e) At least 35.7965 mpg

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = (X - \mu)/(\sigma)$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 33, \sigma = 1.7$

a. P(X<30)

This is the pvalue of Z when X = 30. So

$Z = (X - \mu)/(\sigma)$

$Z = (30 - 33)/(1.7)$

$Z = -1.76$

$Z = -1.76$ has a pvalue of 0.0392.

Then

P(X < 30) = 0.0392.

b) P(28 < X < 32)

This is the pvalue of Z when X = 32 subtracted by the pvalue of Z when X = 28. So

X = 32

$Z = (X - \mu)/(\sigma)$

$Z = (32 - 33)/(1.7)$

$Z = -0.59$

$Z = -0.59$ has a pvalue of 0.2776.

X = 28

$Z = (X - \mu)/(\sigma)$

$Z = (28 - 33)/(1.7)$

$Z = -2.94$

$Z = -2.94$ has a pvalue of 0.0016.

0.2776 - 0.0016 = 0.2760.

P(28 < X < 32) = 0.2760

c) P(X>35)

This is 1 subtracted by the pvalue of Z when X = 35. So

$Z = (X - \mu)/(\sigma)$

$Z = (35 - 33)/(1.7)$

$Z = 1.18$

$Z = 1.18$ has a pvalue of 0.8810.

1 - 0.8810 = 0.1190

P(X > 35) = 0.1190

d. P(X>31)

This is 1 subtracted by the pvalue of Z when X = 31. So

$Z = (X - \mu)/(\sigma)$

$Z = (31 - 33)/(1.7)$

$Z = -1.18$

$Z = -1.18$ has a pvalue of 0.1190.

1 - 0.1190 = 0.8810

P(X > 31) = 0.8810

e. the mileage rating that the upper 5% of cars achieve.

At least the 95th percentile.

The 95th percentile is X when Z has a pvalue of 0.95. So it is X when Z = 1.645. Then

$Z = (X - \mu)/(\sigma)$

$1.645 = (X - 33)/(1.7)$

$X - 33 = 1.645*1.7$

$X = 35.7965$

At least 35.7965 mpg

Need help pleaseeee!

Answers

Answer:

I don't know the answer but I know the formula. Its I=prt

Step-by-step explanation:

Intrerest= principle amount, rate, and time.

Hope this helps!! :)

You are certain to get a heart, diamond, club, or spade when selecting cards from a shuffled deck. Express the indicated degree of likelihood as a probability value between 0 and 1 inclusive.

Answers

Answer:

The probability of this event is represented by a value of 1.

Step-by-step explanation:

Probability of a certain event:

The probability of an event that is considered to be certain, that is, guaranteed to happen, is 100% = 1.

You are certain to get a heart, diamond, club, or spade when selecting cards from a shuffled deck.

This means that the probability of this event is represented by a value of 1.

Colin’s piano lesson is 45 minutes, or 3/4 of an hour, long. If he practices 6 different songs and spends an equal amount of time on each song, what fraction of an hour does he spend practicing each song?

Answers

Answer:

15/2 minutes

Step-by-step explanation:

Class duration= 45 minutes

For 6 songs = 45 minutes

For 1 song = 45/6 = 15/2 minutes

Given:

Colin’s piano lesson is 45 minutes, or Three-fourths of an hour, long. If he practices 6 different songs and spends an equal amount of time on each song, what fraction of an hour does he spend practicing each song ?

Solution:

we have,

→ Colin’s piano lesson is = 45 minutes .

and,

→ he practices total different songs = 6

also, given that, he spends an equal amount of time on each song .

So,

→ Time he spend on each song = Total time of lesson / Total number of songs he practice = 45/6 = (15/2) Minutes.

now, we know that,

→ 60 minutes = 1 hour .

→ 1 minute = (1/60) hour .

then,

→ (15/2) minutes = (1/60) * (15/2) = (1/8) hours.

hope this helps......

Find the area of a parallelogram if a base and corresponding altitude have the indicated lengths. Base 1 1/2 feet, altitude 6 inches. Area = sq. ft. ...?

Answers

area of a parallelogram = A =base*height

so in this case is just (1½)(6).

first off let's convert the mixed fraction to "improper",

$\bf \stackrel{mixed}{1(1)/(2)}\implies \cfrac{1\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{3}{2}} \n\n\n \cfrac{3}{2}\cdot 6\implies \cfrac{18}{2}\implies 9$

Answer:

3/4 sq. ft.

Step-by-step explanation:

The question is using feet and inches. So, you'd have to convert the 6 inches to feet. How many inches in one foot? 6. So 6=1/2 feet so you do 1 1/2*1/2=3/4

The mean of three numbers is 9. the mode of the same three numbers is 7.what is the largest number.

Answers

Answer:

Step-by-step explanation:

9>7

Hopefully, this helps! :D

Other Questions

PLZ HELP ASAP RADIANS AND ARC LENGTH

Which of the following values cannot be probabilities? 0.04, 5 divided by 3, 1, 0, 3 divided by 5, StartRoot 2 EndRoot, negative 0.59, 1.49 Select all the values that cannot be probabilities. A. 1.49 B. 1 C. three fifths D. StartRoot 2 EndRoot E. five thirds F. 0 G. negative 0.59 H. 0.04

Do phone surveys provide adequate coverage of households with respect to one particular parameter? The parameter is the proportion of households without children. If telephone surveys provide adequate coverage of households, then p , the proportion of households without children in the set of all future samples reached by phone, must be equal to the proportion of households without children in the population of all households. Suppose that Thomas, a market analyst, contacts a simple random sample of 300 households as part of a national telephone survey. Of the households contacted, 129 households, or 43 %, have no children and 57 % have at least one child. The most recent census indicates that 48 % of all households have no children and 52 % have at least one child.

T he equation for a parabola with directrix y = –p and focus (0, p) is:1.What is the parabola’s line of symmetry?y-axisx-axisx = px = -p