What are the solutions of 3x^2 +6x +15 =0
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The point of intersection of the lines has an x-coordinate of _____.
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y = 12
hope this helps at all.
you rewrite the second equation as 2x=y and then replace the y in the first equation by 2x
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Answer:
30 minutes
Step-by-step explanation:
Just look at the minutes only. Since you need 4 o'clock to 4:30, its only 30 minutes.
Answer:
30 minutes
Step-by-step explanation:
All you have to do is subtract 4:30 and 4:00 and get 30 minutes.
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Final answer:
The equation for the aircraft's flight is a quadratic equation representing the height of the aircraft at any given time. By rearranging the equation to isolate time and applying the quadratic formula, we can find the time at which the aircraft reaches its maximum height, which in this case is 3.79 minutes.
Explanation:
The flight of an aircraft from Toronto to Montreal is modeled by the equation h = -2.5t2 + 200t where t represents time in minutes and h represents height in meters. This is fundamentally a quadratic equation which is utilized in physics to characterize motion under constant acceleration. In this case, it models the height of the aircraft at any given time.
To find the time at which the airplane's maximum height is achieved, we must solve the equation for t. By rearranging the equation, we can isolate t, yielding a quadratic equation as follows: 0 m = 0 m + (10.0 m/s) t + (2.00 m/s2) t2. This simplifies to 200 = 10t + t2.
Applying the quadratic formula, we find two solutions for t, 3.79 s and 0.54 s. The time it takes the aircraft to reach its maximum height would be the longer solution, which is 3.79 minutes in this case.
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Final answer:
The question provides a quadratic equation to model the flight of an aircraft. This equation can be used to calculate the height of the aircraft at a specific time or to determine when the aircraft reaches its maximum height.
Explanation:
The question is asking about the trajectory of an aircraft as modelled by a quadratic equation, and specifically, how time influences height. The equation given is h = -2.5t²+200t. Quadratic equations are frequently used to describe the motion of objects when the acceleration is constant. This equation tells us that the height of the aircraft is dependent on the time squared and the time.
To solve for a specific time (t), we can plug the desired time into the equation to find the height of the aircraft at that time. For instance, if we want to find out the height of the aircraft 10 minutes into the flight, we would substitute t=10 into the equation, giving us h=-2.5 × (10)²+200 × (10). Simplifying this equation would provide the height of the aircraft 10 minutes into the flight.
Additionally, this equation could also be used to find the maximum height of the aircraft. The maximum height is reached when the derivative of the equation equals zero. Taking the derivative of h = -2.5t²+200t and setting it equal to zero will provide the time when the maximum height is reached.
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Answer:
-250 , -200 , -150 , 0 , 150 , 200 , 300
Step-by-step explanation:
Answer:
-250, -200, -150, 0, 150, 200, 300
Step-by-step explanation:
2nd Ordered Pair
3rd Ordered Pair
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Answer:
what are the ordered pairs?
Final answer:
For the example inequality y > 2x + 1, the ordered pairs that represent solutions include points where the y-coordinate is greater than 2 times the x-coordinate plus one resulting in the pairs (1, 4), (-2, -1), and (0, 2).
Explanation:
The question did not provide a specific inequality, so let's use an example to illustrate. Let's work with the inequality y > 2x + 1. To find
ordered pairs
that are solutions, we need points (x, y) where the y-coordinate is greater than 2 times the x-coordinate plus 1. For example, if we choose x = 1, then we need y > 2*1 + 1 = 3. So, a possible solution is (1, 4). Similarly, if we choose x = -2, then we need y > 2*(-2) + 1 = -3. So, another solution is (-2, -1). Finally, if we choose x = 0, then we need y > 2*0 + 1 = 1. Thus, a third solution is (0, 2). So, the three
ordered pairs
that are solutions to the inequality y > 2x + 1 are (1, 4), (-2, -1), and (0, 2).
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Answer:
perimeter= 2(a + b) mi
area= a×b mi squares
Step-by-step explanation:
Answers:
24 mm², 26.5 mm
Step-by-step explanation:
Area of the triangle:
Perimeter of the triangle:
Hope this helps.