The volume of the jewelrybox is 60 1/2 cubic inches.
The area of a square with a side length of 5 1/2 inches can be found by multiplying the length of one side by itself, giving:
Area = (5 1/2) × (5 1/2) = 30 1/4 square inches
The height of the box is 2 inches.
Therefore, the volume of the jewelry box can be found by multiplying the area of the base by the height of the box, giving:
Volume = Area x Height = (30 1/4) × 2 = 60 1/2 cubic inches
Thus, the volume of the jewelrybox is 60 1/2 cubic inches.
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There are 9 Pink colored sheets.
A branch of mathematics known as algebra deals with symbols and the mathematical operations performed on them.
Variables are the name given to these symbols because they lack set values.
In order to determine the values, these symbols are also subjected to various addition, subtraction, multiplication, and division arithmeticoperations.
given:
Ratio of Red: Pink = 1 :3
let the common ratio be x
If red color sheets are 3.
Then 1x =3
x= 3
Then ,the number of pinksheet s
= 3x
= 3(3)
= 9
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Answer:
Ralph will need 9 sheets of pink paper
Explanation:
The red paper to pink paper ratio is 1 to 3. This means that for every 1 piece of red paper, there are 3 pieces of pink paper. Since there are 3 pieces of red paper that Ralph has, you multiply 3 times 3 to get 9 pieces of pink paper.
To meet the conditions for a hypothesistest assuming independent observations, the sample size should have at least five successes and failures, and the population should be at least 10 or 20 times the size of the sample.
In order to meet the conditions for a hypothesistest that assumes independentobservations in the sample, the sample size should be such that each sample has at least five successes and five failures. Additionally, the population must be at least 10 or 20 times the size of the sample to avoid over-sampling and incorrect results.
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Answer:
A' will coincide with C of the pre image, and B' will coincide with D of the pre image.
Step-by-step explanation:
A Regular Hexagon could be imagined as a circle divided into six points on the circle, that are separated by angles of 60° (notice that 6 times 60° is 360°).
Now we name each point as ABCDEF clockwise, and then we rotate the hexagon about its center (counterclockwise)... the original points ABCDEF are renamed as A'B'C'D'E'F' in the rotated hexagon.
As the rotation was of 240°, the points will coincide with some of the original points: point A will "jump" for points, the same as point B.
This means that point A rotated, (wich is A') will coincide with point C pre rotated, and that point B rotated, (wich is B') will coincide with point D pre rotated.