MATHEMATICS COLLEGE

Professors often attempt to determine if the submissions by the students are genuine or copied off the web sources. The program that performs this task is only 95 % accurate in correctly identifying a genuine submission and 80% accurate in correctly identifying copies. Based on the past statistics, 15% of the student turned in copied work. If a work is identified as a copy by the program, what is the probability that it is indeed a sample of copied work.

Answers

Answer 1

Answer:

Answer:

0.7385 = 73.85% probability that it is indeed a sample of copied work.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = (P(A \cap B))/(P(A))$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Identified as a copy

Event B: Is a copy

Probability of being identified as a copy:

80% of 15%(copy)

100 - 95 = 5% of 100 - 15 = 85%(not a copy). So

$P(A) = 0.8*0.15 + 0.05*0.85 = 0.1625$

Probability of being identified as a copy and being a copy.

80% of 15%. So

$P(A \cap B) = 0.8*0.15 = 0.12$

What is the probability that it is indeed a sample of copied work?

$P(B|A) = (P(A \cap B))/(P(A)) = (0.12)/(0.1625) = 0.7385$

0.7385 = 73.85% probability that it is indeed a sample of copied work.

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In? gambling, the chances of winning are often written in terms of odds rather than probabilities. The odds of winning is the ratio of the number of successful outcomes to the number of unsuccessful outcomes. The odds of losing is the ratio of the number of unsuccessful outcomes to the number of successful outcomes. For? example, if the number of successful outcomes is 2 and the number of unsuccessful outcomes is? 3, the odds of winning are 2:3(Note; if the odds of winning are 2/3, the propability of sucess is2/5)The odds of event occuring are 1:6. Find (a) the propability that the event will occur,(b) propability that the event will not occur.(a)The propability that event will occur is....(TYPE AN INTEGER OR DECIMAL ROUNDED TO THE NEAREST THOUSANDTH AS NEEDED.)(b)The propability thet the event will not occur is...(TYPE AN INTEGER OR DECIMAL ROUNDED TO THE NEAREST THOUSANDTH AS NEEDED)
Evaluate the expression 2x2 - yl yl + 3xº for x = 4 and y = 7

Amy spent $22 on a magazine and fourerasers. If the magazine cost $6, then how
much was each eraser?

Answers

Answer:

Step-by-step explanation:

First, 22-6=16, this isolates how much she spent on erasers alone

Then, 16/4=4, if she bought 4 erasers each one would have cost $4

Step-by-step explanation:

5 dollars and 5 cents.

Which expression is equivalent to 6x+8 PLZZZZZZZZZZZZ HEWLPPP!2(3x-4)
2(3x+4)
2(4x+6)
2(3x+8)

Answers

✽ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ✽

➷ Expand them all to see if you get the expression:

2(3x - 4) ==> 6x - 8

2(3x + 4) ==> 6x + 8

2(4x + 6) ==> 8x + 12

2(3x + 8) ==> 6x + 16

As you can see, the correct option is B. 2(3x + 4)

✽

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ♡

Answer:

So the second one

Step-by-step explanation:

2(3x-4) =6x-8

2(3x+4)=6x+8 2x3=6 2x4=8

2(4x+6)=8x+12

2(3x+8)=6x+16

What is the distance between (3, 5.25) and (3, –8.75)?

Answers

Answer:

The answer is

14 units

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^(2) + ({y1 - y2})^(2) } \n$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(3, 5.25) and (3, –8.75)

The distance between them is

$d = \sqrt{ ({3 - 3})^(2) + ({5.25 + 8.75})^(2) } \n = \sqrt{ {0}^(2) + {14}^(2) } \n = √(196) \: \: \: \: \: \: \: \: \: \: \n = 14 \: \: \: \: \: \:$

We have the final answer as

14 units

Hope this helps you

The mean SAT score in mathematics, M, is 600. The standard deviation of these scores is 48. A special preparation course claims that its graduates will score higher, on average, than the mean score 600. A random sample of 70 students completed the course, and their mean SAT score in mathematics was 613. a) At the 0.05 level of significance, can we conclude that the preparation course does what it claims? Assume that the standard deviation of the scores of course graduates is also 48.

Answers

Answer:

Step-by-step explanation:

The mean SAT score is $\mu=600$ , we are going to call it \mu since it's the "true" mean

The standard deviation (we are going to call it $\sigma$ ) is

$\sigma=48$

Next they draw a random sample of n=70 students, and they got a mean score (denoted by $\bar x$ ) of $\bar x=613$

The test then boils down to the question if the score of 613 obtained by the students in the sample is statistically bigger that the "true" mean of 600.

- So the Null Hypothesis $H_0:\bar x \geq \mu$

- The alternative would be then the opposite $H_0:\bar x < \mu$

The test statistic for this type of test takes the form

$t=\frac{| \mu -\bar x |} {\sigma/√(n)}$

and this test statistic follows a normal distribution. This last part is quite important because it will tell us where to look for the critical value. The problem ask for a 0.05 significance level. Looking at the normal distribution table, the critical value that leaves .05% in the upper tail is 1.645.

With this we can then replace the values in the test statistic and compare it to the critical value of 1.645.

$t=\frac{| \mu -\bar x |} {\sigma/√(n)}\n\n= (| 600-613 |)/(48/\sqrt(70)}\n\n= (| 13 |)/(48/8.367)\n\n= (| 13 |)/(5.737)\n\n=2.266\n$

since 2.266>1.645 we can reject the null hypothesis.

Answer:

The null hypothesis is that the SAT score is not significantly different for the course graduates.

Alternate hypothesis: there is a significant difference between the SAT score achieved by the course graduates as compared to the non-graduates.

Apply the t-test. The Test Statistic value comes out to be t = 1.738 and the p-value = 0.0844

Since the p-value is larger than 0.05, the evidence is weak and we fail to reject eh null hypothesis.

Hope that answers the question, have a great day!

HURRY IM TIMED ON EDGE Which is the best estimate for the percent equivalent to 3/8?26%
279%
37%
38%

Answers

Answer:

C.) 37%

Step-by-step explanation:

$(3)/(8)$ as a percentage is 37.5%

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C. 37%

In Exercise, solve the equation.
ex– 1 = 9

Answers

Answer:

x = ln 10

Step-by-step explanation:

You meant e^x - 1 = 9. Let's isolate e^x, by adding 1 to both sides. We get:

e^x = 10

Now make use of the property ln a = b <=> a = e^b

Then e^x = 10 becomes

x = ln 10

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