Need help in solving this problem. Section is under limits at infinity, horizontal asymptotes...(a) A tank contains 5000L of pure water. Brine that contains 30g of salt per liter of water is pumped into the tank at a rate of 25L/min. Show that the concentration of salt after t minutes (in grams per liter) is
C(t)+ 30t/200+t
(b) what happens to the concentration as t--> infinity?

Answers

Answer 1
Answer:  (a) you can show the concentration by: 

amount of salt / amount of water 


amount of salt 

= 30g / L 

= [ 30 * 25g ] / [ 25L ] , 25L = 1 min 

= [ 30 * 25g ] / min 


amount of water 

= 5000 + 25t 


[ 30 * 25t ] / [ 5000 + 25t ] 

= [ 30 * 25t ] / 25*[ 200 + t ] 

= 30t / [ 200 + t ] yeah 


(b) 


lim t->∞ [ 30t / ( 200 + t ) ] 

= lim t->∞ [ ( (1 / t) * 30t ) / ( (1 / t) * ( 200 + t ) ) ] 

= lim t->∞ [ 30 / ( (200 / t) + 1 ) ] 

= 30 / ( (200 / ∞) + 1 ) 

= 30 / 1 

= 30


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A number x multiplied by 25 is 320.

Using graph paper, determine the line described by the given point and slope. Click to show the correct graph below. (0,6) and -1​

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Answer:

Can't tell

Step-by-step explanation:

Hear me out. There is no graph hear, so I can't answer. Just letting you know

Bonjours !

J'aurais besoin de réponse et t'explication éventuellement :)

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