b. ( 48 + 15 )
c. ( 48 + 30 )
d. ( 24 + 15 )
Answer:
Step-by-step explanation:
Total surface area of a cone =
Since the diagram is half of a cone, its surface area will be
r = radius of the cone
l = slant height
From the diagram diameter of the cone = 16m;
r = 16/2 = 8m
l = 17m
The equation of the line in slope-intercept form is:
Where,
m: slope of the line
b: cutting point with the y axis.
For the slope of the line we have:
Substituting values we have:
Rewriting we have:
Then, we choose an ordered pair:
Substituting values in the generic equation of the line we have:
Rewriting we have:
Answer:
The equation of the line in slope-intercept form is:
Answer:
y =
Step-by-step explanation:
The slope-intercept form is y = mx + b, where "m" is the slope and 'b" is the y-intercept.
Given: G(-6, -4) and E(4, 8)
Now we can use these points G(-6, -4) and E(4, 8) and find the slope.
Slope (m) =
Here x1 = -6, y1 = -4, x2 = 4 and y2 = 8
Plug in these values in the above formula, we get
slope(m) =
=
Slope (m) =
Now we can use the formula (y - y1) = m(x - x1) and find the required equation.
We can plug in m value and (x1, y1) value and find the equation.
y - (-4) = 6/5(x - (-6))
y + 4 = 6/5(x + 6)
Using the distributive property a(b + c) = ab + ac, we get
y + 4 = 6/5 x + 36/5
y = 6/5 x + 36/5 - 4
y =6/5 x +(
y =
b. the integral of the quotient of 1 and the square root of the quantity 1 minus x squared, dx
c. the integral of the quotient of 1 and the square root of the quantity 1 minus x squared, dx
d. the integral of x times the square root of the quantity x squared minus 1, dx
Answer:
B. and C.
General Formulas and Concepts:
Calculus
Differentiation
Integration
U-Substitution
Step-by-step explanation:
*Note:
It seems like B and C are both the same answer.
Let's define our answer choices:
a.
b.
c.
d.
Let's run u-substitution through each of the answer choices:
a.
∴ answer choice A can be evaluated with a simple substitution.
b.
We can see that this integral cannot be evaluated with a simple substitution. In fact, this is a setup for an arctrig integral.
∴ answer choice B cannot be evaluated using a simple substitution.
C.
We can see that this integral cannot be evaluated with a simple substitution. In fact, this is a setup for an arctrig integral.
∴ answer choice C cannot be evaluated using a simple substitution.
D.
Using a little rewriting and integration properties, this integral can be evaluated using a simple substitution.
∴ answer choice D can be evaluated using a simple substitution.
Out of all the choices, we see that B and C cannot be evaluated using a simple substitution.
∴ our answer choices should be B and C.
Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Integration
Book: College Calculus 10e
Answer: A. $5.33
Step-by-step explanation:
I took the test on edge
16 to the power of 1 over 4 equals 4 to the power of 4 to the power of 1 over 4 equals 4 to the power of 4 multiplied by 1 over 4 equals 4
16 to the power of 1 over 4 equals 2 to the power of 8 to the power of 1 over 4 equals 8 to the power of 8 multiplied by 1 over 4 equals 4
16 to the power of 1 over 4 equals 8 to the power of 2 to the power of 1 over 4 equals 2 to the power of 2 multiplied by 1 over 4 equals 8
Answer:
Option A is correct.
Value of 16 to the power of 1 over 4 equals to the power of 4 to the power of 1 over 4 equals 2 to the power of 4 multiplies by 1 over 4 equal 2.
Step-by-step explanation:
To find the value of: 16 to the power of 1 over 4.
we can write 16 as:
⇒
⇒ [∴]
⇒2
Hence, the value of is, 2.
Therefore, the value of 16 to the power of 1 over 4 equals to the power of 4 to the power of 1 over 4 equals 2 to the power of 4 multiplies by 1 over 4 equal 2.
Ans. 16 to the power of 1 over 4 equals 4 to the power of 4 to the power of 1 over 4 equals 4 to the power of 4 multiplied by 1 over 4 equals 4