MATHEMATICS MIDDLE SCHOOL

Which relation is displayed in the graph?A.

{(–4, –3), (2, 2), (2, 1), (0, 3) (–2, 4)}








B.

{(–3, –4), (2, –2), (2, 1), (3, 0) (4, –2)}








C.

{(–3, –4), (–2, 2), (2, 1), (3, 0) (4, –2)}








D.

{(–3, 4), (–2, –2), (1, 2), (3, 0) (4, 2)}
Which relation is displayed in the graph? A. {(–4, –3), - 1

Answers

Answer 1
Answer: The answer is C because you just look at the graph and find out the ordered pairs. So you start at the x axis and then go up the y axis to find the ordered pair.

Answer: C
Answer 2
Answer:

Answer: C. {(–3, –4), (–2, 2), (2, 1), (3, 0) (4, –2)}

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Answers

So to put your equation into algebraic terms, your asking for \frac{\sqrt[3]{7}}{\sqrt[5]{7}} .

Firstly, we have to convert these into fractional exponents. The rule to do that is x^{(m)/(n)}=\sqrt[n]{x^m} . Applying that here, our equation is \frac{7^{(1)/(3)}}{7^{(1)/(5)}}

Next, the rule with dividing exponents with the same base is to just subtract the exponents, so with this we are subtracting 1/5 from 1/3. However, we need to find their LCM, or lowest common multiple, of 3 and 5. You can do this by listing out what numbers 3 and 5 are factors of. In this case, the LCM is 15. Multiply 1/3 by 5/5 and 1/5 by 3/3:

(1)/(3)*(5)/(5)=(5)/(15)\n \n (1)/(5)*(3)/(3)=(3)/(15)\n \n \frac{7^{(5)/(15)}}{7^{(3)/(15)}}

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