B. a boulder falling off a cliff in a straight path
C. a ball being thrown straight up
D. a bicyclist moving in a straight line at a constant speed
Accelerated motion refers to any motion with changing velocity, including changes in speed or direction. Most of the examples provided involve accelerated motion, except for the bicyclist moving in a straight line at a constant speed, as both speed and direction remain constant in such scenario.
In the context of physics, accelerated motion refers to any motion in which the velocity changes - either in magnitude (speed) or direction. This can be due to an increase or decrease in speed, or a change in direction. Examples of accelerated motion include an airplane taking off down a straight runway, a boulder falling off a cliff in a straight path, and a ball being thrown straight up.
However, a bicyclist moving in a straight line at a constant speed is NOT an example of accelerated motion. In this case, the speed (magnitude of velocity) and direction are both constant, and therefore there is no acceleration present.
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Answer:
Diffraction patterns are due to INTERFERENCE.
Explanation:
Once the magnet moved closest to the loop in the forward direction, under reversed magnet polarity, the approximate magnitude of the induced current shown on the galvanometer was mA.
Answer:
2, 2, 2
Explanation:
Answer:
2, 2, 2
Explanation:
correct on edge
b 34.6 m/s
c 0 m/s
d 20 m/s
Vertical component = 40 m/s x sin(60) = 34.6 m/s
Answer: b. 34.6 m/s
The vertical component of velocity is approximately 34.64 m/s. Therefore option B is correct.
When an object is launched at an angle, its velocity can be divided into horizontal and vertical components. The vertical component is found by multiplying the initial velocity by the sine of the launch angle.
To find the vertical component of the velocity, we use trigonometric relationships based on the given launch angle of 60 degrees and initial velocity of 40 m/s.
The vertical component can be calculated as , where v is the initial velocity and is the launch angle.
Calculation:
Given:
Initialvelocity (v) = 40 m/s
Launch angle = 60 degrees
Vertical component:
In this case, with an initial velocity of 40 m/s and a launch angle of 60 degrees, the vertical component of velocity is approximately 34.64 m/s (option b).
Know more about initial velocity:
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