Can anyone help me solve this question? ♂️I will mark as Brainliest for the best step by step explanation
Answers
Answer 1
Answer:
Answer:
Is line
Step-by-step explanation:
I smart
Related Questions
0.74 Kcal/min to cal/secs
William needs to work out the size of angle Y in this diagramOne of William’s reasons are wrong.Write down the correct reason.
My sister is 14 years old. my brother says that his age minus 12 equal to my sister's age.
The numbers 1 through 25 are written in red marker on slips of paper while the numbers 26 through 50 are written with blue marker on slips of paper. All of the papers are put into a bag and shuffled. One card is randomly selected. a) Find the probability of selecting a number greater than 46 or selecting a number written in red. Writing your answer as a fraction and completely simplify. b)Find the probability of selecting a number written in blue or selecting a number tat is multiple of 10. Write your answer as a fraction and completely simplify.
Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x.f(x) = x3 + 4 and g(x) = Cube root of quantity x minus four.
William needs to work out the size of angle Y in this diagramOne of William’s reasons are wrong.Write down the correct reason.
My sister is 14 years old. my brother says that his age minus 12 equal to my sister's age.
The numbers 1 through 25 are written in red marker on slips of paper while the numbers 26 through 50 are written with blue marker on slips of paper. All of the papers are put into a bag and shuffled. One card is randomly selected. a) Find the probability of selecting a number greater than 46 or selecting a number written in red. Writing your answer as a fraction and completely simplify. b)Find the probability of selecting a number written in blue or selecting a number tat is multiple of 10. Write your answer as a fraction and completely simplify.
Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x.f(x) = x3 + 4 and g(x) = Cube root of quantity x minus four.
Answers
Is the inchworm going around the log or over the log?
If it goes over the log, it simply travels the diameter, or 32 cm.
If it goes around the log, then it must travel half of the circumference, or 32*pi/2=16pi cm.
Note that this assumes that the inchworm and the raspberry patch are diametrically opposite.
If it goes over the log, it simply travels the diameter, or 32 cm.
If it goes around the log, then it must travel half of the circumference, or 32*pi/2=16pi cm.
Note that this assumes that the inchworm and the raspberry patch are diametrically opposite.
Maybe I'm overthinking this one, but here's what I think it's talking about.
If I'm wrong, then I ought to at least get a few points for my talent at making
easy things difficult, and inventing obstacles to place in my own path.
-- The worm is 1 inch long.
-- The outside of the log is a cylinder. Its cross-section is a
perfect circle with a circumference of 32-cm.
-- The axis (length) of the log is perpendicular (across) the path
that leads to raspberry nirvana.
-- The ground is hard. The log contacts the ground along a line,
and doesn't sink into it at all.
-- The worm sees the log ahead of him. He continues crawling, until
he is directly under a point on the log that's 1-inch above him.
He then stands up to his full height, sticks his front legs to the log,
hoists himself up onto the bark, and starts to walk up and over it.
-- When he reaches a point on the other side of the log that's exactly 1-inch
above the ground, he hooks his sticky back feet to it, drops straight down to
the ground, and continues on his quest.
-- The question is: What's the length of the part of the log's circumference
that he traveled between the two points that are exactly 1-inch off the ground ?
I thought I was going to be able to be able to talk through this, but I can't.
I need a picture. Please see the attached picture.
Here comes the worm, heading from left to right.
He sees the log in front of him.
He doesn't bother going around it ... he knows he'll be able to get over it.
When he gets under the log, he starts standing straight up, trying to
grab onto the bark. But he can't reach it. He's too short, only 1 inch.
Finally, when he gets to point 'F', the bark is only 1" above him,
so he can hook on and haul himself up to point 'A'.
He continues on ... up, around, and over the log.
Eventually it dawns on him that the log won't last forever, and he'll
soon need to get down to the ground. As he comes down the right
side of the log, he starts looking down. It's too high. He can't reach
the ground, and he's afraid to jump.
Then he reaches point 'B'. It's exactly 1-inch above the ground, and
he leaves the log and gets down.
What was the length of the path he followed on the log ... the long way,
over the top from 'A' to 'B' ?
Here's what I did:
Draw radii from the center of the log to 'A' and 'B' .
Each of them is 16 cm long (1/2 of the diameter).
Draw the radius from the center of the log to the ground (' E ').
It's 16 cm all the way.
Point 'D' is 1 inch = 2.54 cm above the ground, so the
vertical leg of each little right triangle is (16 - 2.54) = 13.46 cm.
There are two similar right triangles, back to back, inside the log.
They are 'CAD' on the left, and 'CBD' on the right.
I want to know the size of the angles at the top of each triangle.
(One will be enough, since they're equal angles.)
For each of those angles, the side adjacent to it is 13.46 cm.
And the hypotenuse of each right triangle is a radius, so it's 16 cm.
The cosine of those angles is (adjacent/hypotenuse) = 13.46/16 = 0.84125 .
Each angle is 32.73 degrees.
Both of them put together add up to 65.45 degrees .
The full circumference of the log is (pi)(D) = 32pi cm.
The short arc between 'A' and 'B' is (65.45/360) of the full circumference.
The rest of the circumference is the distance that the worm crawled along it.
That's (1 - 65.45/360) times (32 pi) = (0.818) x (32 pi) = 82.25 cm .
Having already wasted enough time on this one in search of 5 points,
and then gone back through the whole thing to make corrections for
the customary worm crawling over the metric log, I'm not going to bother
looking for a way to check it.
That's my answer, and I'm sticking to it.
Answers
Notes:
The notation ">=" without quotes means "greater than or equal to"
The upper case "U" means "set union"
Instead of using the intersection symbol, I will use a lower case 'n'
-------------------------------
Problem 1
A = {x | x < 1} which is the set of x values smaller than 1
B = {x | x >= 5} is the set of x values that are equal to 5 or larger
A U B = set of values that are from set A OR they are from set B (or both)
A U B = {x | x < 1 or x >= 5}
we simply connect the two inequalities mentioned with an "or"
note: how there is no overlap between the two regions. The "U" means "set union" which is like a sort of glue to tie the two sets together with an "or".
Answer: {x| x < 1 or x >= 5}
-------------------------------
Problem 2
A = {x | x < 1}
C = {x | x = 5} which is the set of one value only: 5 (x cannot equal any other value)
A U C = {x| x < 1 or x = 5}
So if a number is in set A U C, then this number is either less than 1, OR it is equal to 5
Answer: {x|x < 1 or x = 5}
-------------------------------
Problem 3
B U C = {x | x >= 5} because set C already has the "or equal to" part in there.
Set C is a subset of set B. If an item is in set C, then it is also in set B.
Answer: {x| x >= 5}
-------------------------------
Problem 4
Again recall that I'm using an 'n' to indicate "set intersection" instead of the upside down "U" symbol
A n B is the set of items that are in BOTH sets A and B at the same time. From problem 1, I mentioned there's a gap. There is no x value that is both less than 1 AND greater than or equal to 5. So this means that
A n B = empty set
which we use the "O" with a slash through it. This is a special symbol to indicate "empty set"
Another way to write "empty set" is to use curly braces with nothing inside like so { }
Answer: The "O" with a slash through it
-------------------------------
Problem 5
B n C is the same as {x| x = 5}
Why? Because if an item is in B n C, then it has to be in BOTH set B and set C at the same time. The only way this happens is if x = 5. If x is any other value, then it won't be in set C
Answer: {x| x = 5}
The notation ">=" without quotes means "greater than or equal to"
The upper case "U" means "set union"
Instead of using the intersection symbol, I will use a lower case 'n'
-------------------------------
Problem 1
A = {x | x < 1} which is the set of x values smaller than 1
B = {x | x >= 5} is the set of x values that are equal to 5 or larger
A U B = set of values that are from set A OR they are from set B (or both)
A U B = {x | x < 1 or x >= 5}
we simply connect the two inequalities mentioned with an "or"
note: how there is no overlap between the two regions. The "U" means "set union" which is like a sort of glue to tie the two sets together with an "or".
Answer: {x| x < 1 or x >= 5}
-------------------------------
Problem 2
A = {x | x < 1}
C = {x | x = 5} which is the set of one value only: 5 (x cannot equal any other value)
A U C = {x| x < 1 or x = 5}
So if a number is in set A U C, then this number is either less than 1, OR it is equal to 5
Answer: {x|x < 1 or x = 5}
-------------------------------
Problem 3
B U C = {x | x >= 5} because set C already has the "or equal to" part in there.
Set C is a subset of set B. If an item is in set C, then it is also in set B.
Answer: {x| x >= 5}
-------------------------------
Problem 4
Again recall that I'm using an 'n' to indicate "set intersection" instead of the upside down "U" symbol
A n B is the set of items that are in BOTH sets A and B at the same time. From problem 1, I mentioned there's a gap. There is no x value that is both less than 1 AND greater than or equal to 5. So this means that
A n B = empty set
which we use the "O" with a slash through it. This is a special symbol to indicate "empty set"
Another way to write "empty set" is to use curly braces with nothing inside like so { }
Answer: The "O" with a slash through it
-------------------------------
Problem 5
B n C is the same as {x| x = 5}
Why? Because if an item is in B n C, then it has to be in BOTH set B and set C at the same time. The only way this happens is if x = 5. If x is any other value, then it won't be in set C
Answer: {x| x = 5}
Answers
Answer:
C = 81.6 degrees
Step-by-step explanation:
The formula for law of sines
sin A sin B sin C
-------- = ----------- = -------------
a b c
Looking at the diagram, we know A = 54, b = 7.4 and c = 15.8
not enough to use the law of sines
We will need to use the law of cosines
a^2 = b^2 + c^2 - 2ac cos A
Using the law of cosines, we can calculate the length of a
a^2 = 7.4^2 + 15.8^ -2*7.4*15.8 cos 54
a^2 = 54.6+249.64-233.84cos54
a^2 =166.7922966
a = 12.921
Now we can use the law of sines to find C
sin 54 sin C
-------- = -------------
12.921 15.8
Using cross products
15.8 * sin 54 = 12.921 * sin C
Divide each side by 12.921
15.8 /12.921 * sin 54 = sin C
Take the arcsin of each side
arcsin (15.8 /12.921 * sin 54) = arcsin (sin C)
arcsin (15.8 /12.921 * sin 54) = C
C = 81.6 degrees
30
B.
2
C.
24
D.
360
Answers
The answer would be 30 :)
f(x) = –3x^2 – 3x + 2
f(x) = –3x^3 + 2
f(x) = 2x^2 + 3x – 3
Answers
quadatic means 2nd degree, means highest exponent of placeholder is 2
leading coefient is the number that is in front of the highest power x
constant term is the one that doesn't have an x witht it
quadratic
2nd and last fn are quadratic
leading coefient of 2 is first and last fn
constant term is -3 for first and last fn
answer is last function
leading coefient is the number that is in front of the highest power x
constant term is the one that doesn't have an x witht it
quadratic
2nd and last fn are quadratic
leading coefient of 2 is first and last fn
constant term is -3 for first and last fn
answer is last function
Answers
Answer:
33
Step-by-step explanation:
just coint how much is on each side then multiply it by 3
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